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3 years ago

EASY MATH PROBLEM EASY POINTS!!!

Mathematics

2 answers:

marishachu [46]3 years ago

5 0

Answer:

a. $9(3^0)=9(1)=9$

No.

Step-by-step explanation:

Any number to the 0th power is 1, so we can set y to any value we want, and $9y^0$ will always come out to $9(1)=9$

Radda [10]3 years ago

4 0

Answer:

Its A YEET NO.

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A circle has its center at (1,4) and a radius of 2 units what is the equation of the circle

joja [24]

Answer: x² + y² - 2x - 8y + 13 = 0

Step-by-step explanation:

the equation of the circle is in the form (x - a)² + (y - b)² = r²

where (a,b) is the center of the circle and r is the radius

hence the equation is

(x - 1)² + (y - 4)² = 2²

x²-2x+1+y²-8y+16= 4

x²+ y² -2x- 8y + 17 =4

x² + y² - 2x - 8y = -13

x² + y² - 2x - 8y + 13 = 0

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3 years ago

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Do you know how do this because I need help?

kobusy [5.1K]

Answer:

B/ x=4

Step-by-step explanation:

Just take 2x to another side to be neg-, the same thing with 4 , then divide it both sides by 4 to get the answer.

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3 years ago

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Will mark brainly if correct please help

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App 19.study

HACTEHA [7]

Answer:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

Step-by-step explanation:

Given

$n = 125$

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

$Pr = \frac{Frequency}{n}$

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

$Pr(2) = \frac{13}{125} = 0.104$

$Pr(4) = \frac{29}{125} = 0.232$

$Pr(6) = \frac{6}{125} = 0.048$

When the frequency is to be calculated, we use:

$Pr = \frac{Frequency}{n}$

$Frequency = n * Pr$

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

$Frequency(3) = 125 * 0.144 = 18$

$Frequency(5) = 125 * 0.296 = 37$

For roll of 1 where the frequency and the probability are not known, we use:

$Total \ Frequency = 125$

So:

Frequency(1) added to others must equal 125

This gives:

$Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125$

$Frequency(1) + 103 = 125$

Collect like terms

$Frequency(1) =- 103 + 125$

$Frequency(1) =22$

The probability is then calculated as:

$Pr(1) = \frac{22}{125}$

$Pr(1) = 0.176$

So, the complete table is:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

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3 years ago

What is the simplified form of the following expression? (y^8)(y^2)

IrinaVladis [17]

A. Y^10
This is the answer because the problem is simple. In my math class we use KBAE which is Keep base add exponents so I used that and I got y^10.

REALLY hope this helps :)

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3 years ago

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