The cheap answer is, well, all we do is, grab the denominator of one and multiply the other by it, top and bottom, and grab the denominator of the other, and multiply the first one by that one too, that way, both will have the same denominator, and then you can simply check the numerator to see who's larger, let's do so.
surely you can tell.
Answer:
15.1
Step-by-step explanation:
29.34
-14.24
---------
15.10
Answer:
2. option D and 3. option A
Step-by-step explanation:
2. 7 + y = 30
<u>7 - 7</u> + y = <u>30 - 7</u>
y = 23
3. w - 32 = 55
w <u>-</u><u> </u><u>32</u><u> </u><u>+</u><u> </u><u>32</u> = <u>55</u><u> </u><u>-</u><u> </u><u>32</u>
w = 87
Basically the answers you choose are right. Hope this helps, thank you :) !!
Ya, calculus and related rates, such fun!
everything is changing with respect to t
altitude rate will be dh/dt and that is 1cm/min
dh/dt=1cm/min
area will be da/dt which is increasing at 2cm²/min
da/dt=2cm²/min
base=db/dt
alright
area=1/2bh
take dervitivie of both sides
da/dt=1/2((db/dt)(h)+(dh/dt)(b))
solve for db/dt
distribute
da/dt=1/2(db/dt)(h)+1/2(dh/dt)(b)
move
da/dt-1/2(dh/dt)(b)=1/2(db/dt)(h)
times 2 both sides
2da/dt-(dh/dt)(b)=(db/dt)(h)
divide by h
(2da/dt-(dh/dt)(b))/h=db/dt
ok
we know
height=10
area=100
so
a=1/2bh
100=1/2b10
100=5b
20=b
so
h=10
b=20
da/dt=2cm²/min
dh/dt=1cm/min
therefor
(2(2cm²/min)-(1cm/min)(20cm))/10cm=db/dt
(4cm²/min-20cm²/min)/10cm=db/dt
(-16cm²/min)/10cm=db/dt
-1.6cm/min=db/dt
the base is decreasing at 1.6cm/min
