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3 years ago

What times 3 equals something that is divisible by 2 that equals 8?

Mathematics

1 answer:

Delicious77 [7]3 years ago

8 0

Let the unknown be n, then: n × 3 = 8 × 2 n × 3 = 16 n = 16 ÷ 3 n = 5.333

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Which ordered pair is the solution to the system of equations? {x+3y=-12, y= 1/3x-6?

Julli [10]

For this, I'll be using the substitution method. Since y = 1/3x - 6, replace the y variable in the first equation with 1/3x - 6 and solve for x:

$x+3(\frac{1}{3}x-6)=-12\\ x+x-18=-12\\ 2x-18=-12\\ 2x=6\\ x=3$

Now that we have the value of x, plug it into either equation to solve for y:

$3+3y=-12\\ 3y=-15\\ y=-5\\ \\ y=\frac{1}{3}*3-6\\ y=1-6\\ y=-5$

<h3><u>In short, the solution to this equation is (3,-5).</u></h3>

5 0

3 years ago

Hello! So, Given the equation y = 2x - 8, what is the slope and the y-intercept? Please help with a good explanation of how you

elena55 [62]

Answer:

m = 2 and b = -8.

Step-by-step explanation:

One of the most commonly used equations of straight lines is y = mx + b, where m is the slope and b is the y-intercept.

Comparing the given y = 2x - 8 to y = mx + b, we see that m = 2 and b = -8.

3 0

4 years ago

Read 2 more answers

The semiannual tuition payment at a major university is expected to be $30,000 for the 4 years beginning 18 years from now. What

elena-14-01-66 [18.8K]

Answer:

$49,216.78

Step-by-step explanation:

A(n,k) = R[1-(1+i)^-n / i) (1+i)^-k

A = Present value of deferred annuity

R = Payment at the end of period

R = 30,000

i = 0.06 / 2

n = (4)*2 = 8

k = deferred period, (18)*(2) = 36

A(n,k) = 30,000*(1-(1+0.04)-^8 / 0.04)*(1+0.04)^-36

A(n,k) = 30,000*(1-(1.04)^-8 / 0.04)*(1.04)^-36

A(n,k) = 30,000*(1 - 0.730690205/0.04) * 0.24366872185

A(n,k) = 30,000*(0.269309795 / 0.04)*0.24366872185

A(n,k) = 30,000*6.732744875*0.24366872185

A(n,k) = 49216.78014700164

A(n,k) = $49,216.78

So the lump sum payment that the university accept now is $49,216.78

6 0

3 years ago

Find the sum of 5 m + 3 n + p , -5 p + 3 n , and 2 n - m .

tatyana61 [14]

Equal to 3n+p
i think thats it

8 0

3 years ago

the circular ripple caused by dropping a stone in a pond is increasing in area at a constant rate of 20 square meters per second

mojhsa [17]

Answer:

2/π ≈ 0.637 m/s

Step-by-step explanation:

The rate of change of area with respect to time is ...

A = πr²

dA/dt = 2πr·dr/dt

Filling in given values in the above equations, we can find r and dr/dt.

25π = πr² ⇒ r = 5

20 = 2π·5·dr/dt

dr/dt = 20/(10π) = 2/π . . . . meters per second

The radius is increasing at the rate of 2/π ≈ 0.637 meters per second.

4 0

3 years ago