Rowan is taking his siblings to get ice cream. They can't decide whether to get a cone or a cup because they want to get the mos t ice cream for their money. If w = 4 in, x =6 in, y = 6 in, z = 2 in, and the cone and cup are filled evenly to the top with no overlap, which container will hold the most ice cream? Use 3.14 for π, and round your answer to the nearest tenth. a cone with a height of x and a radius of w, a cylinder with a diameter of y and a height of z
please help me
2 answers:
Answer:
Step-by-step explanation:
Cone: volume is V = πr²h. If r = w = 4in and h = z = 2 in, then the volume of the ice cream cone would be
Cone: V = (1/3) π (4 in)² (2 in) = (1/3) (32π) in³
Cup: Volume (assumed to be cylindrical) is V = π r² h, which here would be V = π (y/2)² z = π (6 ²/ 4) (2 in) = π (9 in² (2 in) = V = 18 π in³
Comparing the volumes of the cone and the cup, we get the ratio\
32/3
-------- or approximately (cone / cup): 11/18. The cup has the greater
18 volume.
Answer:
The cup holds 43.96 in^3 more ice cream than the cone.
<em>I got this problem and chose the other answer that said that the cup was more, which was</em>
<em />
<em>"The cup holds 56.52 in^3 more ice cream than the cone."</em>
<em />
<em>and </em><u><em>I got it wrong</em></u><em>.</em>
<em />
The cup holds 43.96 in^3 more ice cream than the cone.
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Step-by-step explanation:
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a3 = 11
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Computation:
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From Eq2 - Eq1
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Step-by-step explanation:
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