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Sphinxa [80]
3 years ago
5

Calculate the surface area of a piston with a diameter of 2.25inches

Mathematics
1 answer:
Talja [164]3 years ago
6 0

i cant tell you that it is from a test

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Rewards for answering the question below will be in place.
nadya68 [22]

Answer:

It is the distance that - 5 is from 0 on the number line.

Step-by-step explanation:

We have to select a statement that is true about the value of StartAbsoluteValue negative 5 EndAbsoluteValue i.e. |- 5|

Definition of the absolute value function is given by, |x| = x for, x ≥ 0 and |x| = - x for x < 0.

Now, an absolute value function gives the positive value of any value in the function i.e. |- 5| = 5.

Therefore, it is the distance that - 5 is from 0 on the number line. (Answer)

6 0
3 years ago
Read 2 more answers
Abbie has to do 25 math problems tonight. She has completed 40%. How many problems has she completed?
erik [133]

Answer:

10

Step-by-step explanation:

0.4*25

7 0
3 years ago
-1/2m=-9 what does m=
lilavasa [31]

Answer:

m = 18

Step-by-step explanation:

Step 1: Write out equation

-1/2m = -9

Step 2: Multiply both sides by -2

m = 18

5 0
3 years ago
Please help this is the last problem I need
tangare [24]

Answer:

sin 54 = \frac{x}{14}

Step-by-step explanation:

sine = \frac{opposite}{hypotenuse}

Side z is the adjacent, since it is next to the angle you are solving for.

Side x is the opposite, since it is opposite the angle you are solving for.

The side measuring 14 is the hypotenuse, since it is across from the right angle.

sin 54 = \frac{x}{14}

8 0
3 years ago
Determine the point of intersection of right bisectors in a triangle ∆ with vertices A (-3, 5), B (1, 1) and (−7, −3). Find the
iris [78.8K]

Answer:

Point of intersection (-11/3 , 1/3)

All distances from the vertices are \frac{10\sqrt{2} }{3}

Step-by-step explanation:

The vertices of the triangle is A(-3,5) , B (1,1) and C (-7,-3)

We need to find the perpendicular bisector of the triangle first

let's take one side connecting A and B

mid point of A and B = (-1,3)

Slope of the line joining A and B = -1

slope of perpendicular to line joining A and B = 1

equation of line passing through (-1,3) with slope 1

y - 3 = 1(x-(-1))

y -3 = x+1

x-y = -4 ............(1)

similarly

mid point joining B and C = (-3,-1)

slope perpendicular to line joining B and C  =  -2

Equation of perpendicular bisector of line joining B and C =

y +1 = -2(x +3 )

y+1 = -2x -6

2x+y = -7 ..........(2)

On solving 1 and 2

x= -11/3 , y= 1/3

Distances

From A = \frac{10\sqrt{2} }{3}

From B = \frac{10\sqrt{2} }{3}

From C = \frac{10\sqrt{2} }{3}

7 0
2 years ago
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