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d1i1m1o1n [39]
3 years ago
6

Find the general (explicit) solution to the differential equation: dy dx = y4 cos x

Mathematics
1 answer:
Levart [38]3 years ago
5 0
Try this solution:dy/dx=y⁴cosx; y⁻⁴dy=cosxdx;  \int\ {y^{-4}} \, dy= \int\ {cosx} \, dx;- \frac{1}{3y^3}=sinx+C; \ =\ \textgreater \  \ y^3=-  \frac{1}{3sinx+C}

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