Answer:
The median for the students is 2 and the median for the teachers is 3.
Step-by-step explanation:
Answer:
Arcsin(1/5) = 0.20
Arcsin(-0.34) = -0.35
Arcsin(0.6) = 0.64
Step-by-step explanation:
Using a calculator we can find the value of each expression:
Arcsin(1/5) = 0.20135792079, rounding to the nearest hundredth we have that: Arcsin(1/5) = 0.20.
Arcsin(-0.34) = -0.346916897527, rounding to the nearest hundredth we have that: Arcsin(-0.34) = -0.35
Arcsin(0.6) = 0.643501108793, rounding to the nearest hundredth we have that: Arcsin(0.6) = 0.64
Dy/dx = y/(x^2)
dy/y = dx/(x^2)
int[dy/y] = int[dx/(x^2)] ... apply integral to both sides
ln(|y|) = (-1/x) + C
|y| = e^{(-1/x) + C}
|y| = e^C*e^(-1/x)
|y| = C*e^(-1/x)
y = C*e^(-1/x)
So you have the correct answer. Nice job.
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Check:
y = C*e^(-1/x)
dy/dx = d/dx[C*e^(-1/x)]
dy/dx = d/dx[-1/x]*C*e^(-1/x)
dy/dx = (1/(x^2))*C*e^(-1/x)
is the expression for the left hand side (LHS)
y/(x^2) = [C*e^(-1/x)]/(x^2)
y/(x^2) = (1/(x^2))*C*e^(-1/x)
is the expression for the right hand side (RHS)
Since LHS = RHS, this confirms the solution for dy/dx = y/(x^2)
Answer:
The question, 'How much do the dogs in the pound weigh?' is the statistical question.
Hope this helps.
Answer:
-16
Step-by-step explanation:
as you know you cant add positives so the answer would be a negative
ok so what plus 4 equals 20? 16.
therefore: -16
