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aivan3 [116]
3 years ago
11

Write the equation for the following table: 0 2 1 7 2 13 3 20

Mathematics
2 answers:
Lana71 [14]3 years ago
7 0
Sorry I do not know math that well but I did search on Google and what the other user answered was correct, so a bravo!♡︎♥︎
sveta [45]3 years ago
5 0

Answer:

Step-by-step explanation:

for each positive integer m, so that la - r2m-ll and la - r2m I are both less than

1 1

Ir2m - r2m-ll .:::: 42(m-l) Ir2 - rll = 24m - 3 ·

It follows that limn--->oo rn = limn--->oo rn-l = a. Taking limits in the recursion in

(d) leads to

1

a=I+--

l+a

which reduces to a 2 = 2. Since rn > 0 for each n, a > O.

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The answer might be Y=1/4x+2
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What are the solutions of the equation x^4-5x-^2-14=0
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3 years ago
What is the correct solution set for the following graph?
Serhud [2]

Answer: i do not see a graph

Step-by-step explanation:

8 0
3 years ago
Help plz !!!!! Isosceles and Equilateral.
Ilya [14]
Answer: 40

=====================================

Explanation:

The angle we want is QPR (bottom left), which is one of the base angles. The other base angle is QRP (bottom right). These two angles are equal because PQR is an isosceles triangle (PQ = RQ)

So if we can find angle QRP, then we have found angle QPR

Note how angle QRP and the 140 degree angle combine to form a straight 180 degree angle. Therefore these two angles add to 180 degrees

(angle QRP) + (140) = 180
(angle QRP) + 140 - 140 = 180-140 ... subtract 140 from both sides
angle QRP = 40

Since,
angle QPR = angle QRP
this means
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8 0
3 years ago
On moving day, Guyton needs to rent a truck. The length of the cargo space is , and the height is less than the width. The broch
Neporo4naja [7]

On moving day, Guyton needs to rent a truck. The length of the cargo space is 10 ft , and the height is 1 ft less than the width. The brochure indicates that the truck can hold 420 ft3 . What are the dimensions of the cargo space? Assume that the cargo space is rectangular shape.

Answer:

The dimensions; width w is 7 ft and height is 6 ft

Step-by-step explanation:

L = 10 ft the length of the cargo space

w = the width of the cargo space

h = the height of the cargo space the height is 1 ft less than the width

h = w - 1

The truck can hold 420 ft^3 - this means the volume of the space V = 420 ft^3

But V = L*w*h

Substitute h = w - 1 into the Volume equation

Therefore,

10*w*(w - 1) = 420

10w^2 - 10w - 420 = 0

By Using quadratic equation formula to solve and considering positive answer,

w = {-b +- √(b^2 - 4ac)}/2a

Where;

a = 10, b = -10 and c = -420

w = {-(-10) +- √(-10^2 - 4(10)(-420)}/2(10)

w = {-(-10) +- 130}/20

w = (10 + 130)/20 = 140/20 = 7

Or

w = (10 -130)/20 = -120/20 = -6

Here,

I take positive answers and the width is 7 ft

Also, from h = w - 1

height = 7 - 1 = 6 ft

5 0
4 years ago
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