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3 years ago

8

At an automobile plant, each car is inspected by 34 different workers before it is shipped to a dealer. One day, workers perform

ed 9,690 inspections. How many cars were shipped?

1 answer:

nirvana33 [79]3 years ago

8 0

Answer: 285

Step-by-step explanation:\

9,690/34=285

285 cars were shipped

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One day I found a strange thing happening to my watch,the minute hand & the hour hand were coming together every 65 minutes.

brilliants [131]

Answer:

Step-by-step explanation:

The minute hand of a clock overtakes the hour hand at intervalsof M minutes of correct time. The clock gains or loses in a day by=(720/11−M)(60×24/M) minutes.

Here M = 64. The clock gains or losses in a day by

=(720/11−M)(60×24/M)=(720/11−64)(60×24/64)

=16/11(60×3/8)=2/11(60×3)=360/11=32(8/11) minutes.

5 0

3 years ago

A multiple-choice examination has 15 questions, each with five answers, only one of which is correct. Suppose that one of the st

Alex

Answer:

0.0111% probability that he answers at least 10 questions correctly

Step-by-step explanation:

For each question, there are only two outcomes. Either it is answered correctly, or it is not. The probability of a question being answered correctly is independent from other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A multiple-choice examination has 15 questions, each with five answers, only one of which is correct.

This means that $n = 15, p = \frac{1}{5} = 0.2$

What is the probability that he answers at least 10 questions correctly?

$P(X \geq 10) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.2)^{10}.(0.8)^{5} = 0.0001$

$P(X = 11) = C_{15,11}.(0.2)^{11}.(0.8)^{4} = 0.000011$

$P(X = 12) = C_{15,12}.(0.2)^{12}.(0.8)^{3} \cong 0$

$P(X = 13) = C_{15,13}.(0.2)^{13}.(0.8)^{2} \cong 0$

$P(X = 14) = C_{15,14}.(0.2)^{14}.(0.8)^{1} \cong 0$

$P(X = 15) = C_{15,15}.(0.2)^{15}.(0.8)^{0} \cong 0$

$P(X \geq 10) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.0001 + 0.000011 = 0.000111$

0.0111% probability that he answers at least 10 questions correctly

3 0

3 years ago

Mark spends a total of $68.82 for 2 pairs of sneakers with the same cost. The sales tax is $5.32. Mark also uses a coupon for $3

shutvik [7]

Each pair of sneakers cost $33.25

Step-by-step explanation:

Given,

Total spent by Mark = $68.82

Sales tax = $5.32

Coupon used = $3.00

Price without sales tax = Total spent - sales tax

Price without sales tax = 68.82 - 5.32 = $63.50

As Mark used coupon, we will add this amount.

Amount of sneakers = Price without sales tax + Coupon used

Amount of sneakers = 63.50+3.00 = $66.50

As this is price of two sneakers, we will divide it by 2;

Cost of one sneaker = $\frac{66.50}{2}=\$33.25$

Each pair of sneakers cost $33.25

Keywords: subtraction, addition

Learn more about addition at:

#LearnwithBrainly

5 0

3 years ago

Please help i never learned this yet lol (Will mark brainliest!!) <br> thx!! :)

galben [10]

Answer:

C

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Please answer the questions that are attached will give extra points!

faltersainse [42]

Thank you very much and this “question” was very helpful for me.

6 0

3 years ago