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slavikrds [6]
3 years ago
14

Funcion cuadratica -3x(2)-6x+5

Mathematics
1 answer:
Bond [772]3 years ago
3 0

Answer:

-12x + 5

Step-by-step explanation:

-3x(2)-6x+5

-6x-6x+5

-12x + 5

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In triangle ABC, the measure of C is 90°,<br> AC=24, and BC=10. What is the value of sin<br> A?
Sergio039 [100]

Answer:

Sin A = 0.38462

Step-by-step explanation:

From the trigonometric function,

Sin A = \frac{Opposite}{Hypotenuse}  ................... 1

So that, applying the Pythagoras theorem to determine the value of hypotenuse,

/Hyp/^{2} = /Opp/^{2} + /Adj/^{2}

            = 24^{2} + 10^{2}

            = 576 + 100

/Hyp/^{2} = 676

Hyp = \sqrt{676}

       = 26

The hypotenuse of the triangle is 26.

Thus, from equation 1;

Sin A = \frac{10}{26}

Sin A = 0.38462

7 0
3 years ago
Harry started a new job in 2003. His salary was $31,000. At the beginning of the next year he will receive a raise of $1500. Ass
Anton [14]

Answer:

Step-by-step explanation:

a)

S=31000+1500Y  

Where S is salary and Y is # of years  

b)  

 

Salary in 5 years;  

=31000+1500(5)  

=31000+7500  

=38500  

6 0
3 years ago
Read 2 more answers
Which equation represents the graph of the linear function?
mojhsa [17]
The answer us b because the y intercept is -1 and the slope is 2/-1
3 0
3 years ago
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24x-9 solve<br> A 3(8x - 9)<br> B 6(4x - 9)
Hitman42 [59]
24 x -9 or 24x - 9?
then I will answer :))
8 0
3 years ago
Find the sum of the first 16 terms of an arithmetic sequence where a4=7 and a7= 16. (I need the procedure y Example) please
Luden [163]

Answer:

S₁₆ = 328

Step-by-step explanation:

the nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

given a₄ = 7 and a₇ = 16 , then

a₁ + 3d = 7 → (1)

a₁ + 6d = 16 → (2)

subtract (1) from (2) term by term to eliminate a₁

0 + 3d = 9

3d = 9 ( divide both sides by 3 )

d = 3

substitute d = 3 into (1) and solve for a₁

a₁ + 3(3) = 7

a₁ + 9 = 7 ( subtract 9 from both sides )

a₁ = - 2

the sum to n terms of an arithmetic sequence is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ]

with a₁ = - 2 and d = 3 , then

S₁₆ = \frac{16}{2} [ (2 × - 2) + (15 × 3) ]

     = 8(- 4 + 45)

     = 8 × 41

     = 328

6 0
2 years ago
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