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Cerrena [4.2K]
2 years ago
13

5^2•3^-1•5^-3/3^4•5^-1•3^-3

Mathematics
1 answer:
puteri [66]2 years ago
3 0
Assuming you want the expression to be simplified. 

We begin with the following: 

5^{2} * 3^{-1} * \frac{5^-3}{3^{4}} * 5^{-1} * 3^{-3}

Simplify the first part, 5^{2}. That is 25. Now we have this: 

25*3^{-1.5} * \frac{-3}{3^{4}} * 5^{-1} * 3^{-3} 

Next, simplify 3^{-1}, which is 1/3, and get this: 

25* 1/3 * \frac{-3}{3^{4}} * 5^{-1} * 3^{-3} 

The next part is \frac{5^-3}{3^{4}}. Simplify the denominator, 3^{4}, which is 81. Simplify the numerator, which is 1/125. Then divide 1/125 by 81, which we will keep as a fraction for simplicity's sake, but simplify it to \frac{1}{10125}. Now we have: 

25* 1/3 * \frac{1}{10125} * 5^{-1} * 3^{-3}

Now simplify 5^{-1}, which is 0.2, or 1/5. Now we have: 

25* 1/3 * \frac{1}{10125} * 0.2 * 3^{-3} 

Finally, simplify 3^{-3}. That is 1/27. We have: 

25* 1/3 * \frac{1}{10125} * 0.2 * 1/27

Lastly, multiply them all together! Now we are done, with the product of: 

\frac{1}{6075}

That certainly did take a while to type in all the LaTex, so I really hope that helped!

Note- if anything isn't working with the LaTex, just tell me and I'll fix it! (:
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Answer:

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Step-by-step explanation:

Given data

initial number of stores P= 200

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A= P(1+r)^t

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4 0
2 years ago
A map has a scale of 2 inches = 15 miles.If two towns are 7 inches apart on the map,how far apart are they actually
seraphim [82]
1.) set up a w_k_u chart
2.) in the w column write in on top and mi in the bottom like this
w_K_U
in_
mi_
then in the k column write 2 for in and 15 for mi
W_K_U
in_2_
mi_15_
then in the U column, you write 7 for in and x for mi
W_K_U
in_2_7
mi_15_x
then cross multiply:  2x = 15(7)
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Answer:

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Step-by-step explanation:

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