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Cerrena [4.2K]
3 years ago
13

5^2•3^-1•5^-3/3^4•5^-1•3^-3

Mathematics
1 answer:
puteri [66]3 years ago
3 0
Assuming you want the expression to be simplified. 

We begin with the following: 

5^{2} * 3^{-1} * \frac{5^-3}{3^{4}} * 5^{-1} * 3^{-3}

Simplify the first part, 5^{2}. That is 25. Now we have this: 

25*3^{-1.5} * \frac{-3}{3^{4}} * 5^{-1} * 3^{-3} 

Next, simplify 3^{-1}, which is 1/3, and get this: 

25* 1/3 * \frac{-3}{3^{4}} * 5^{-1} * 3^{-3} 

The next part is \frac{5^-3}{3^{4}}. Simplify the denominator, 3^{4}, which is 81. Simplify the numerator, which is 1/125. Then divide 1/125 by 81, which we will keep as a fraction for simplicity's sake, but simplify it to \frac{1}{10125}. Now we have: 

25* 1/3 * \frac{1}{10125} * 5^{-1} * 3^{-3}

Now simplify 5^{-1}, which is 0.2, or 1/5. Now we have: 

25* 1/3 * \frac{1}{10125} * 0.2 * 3^{-3} 

Finally, simplify 3^{-3}. That is 1/27. We have: 

25* 1/3 * \frac{1}{10125} * 0.2 * 1/27

Lastly, multiply them all together! Now we are done, with the product of: 

\frac{1}{6075}

That certainly did take a while to type in all the LaTex, so I really hope that helped!

Note- if anything isn't working with the LaTex, just tell me and I'll fix it! (:
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3 years ago
F is a polynomial of degree 6. f has a root of multiplicity
frutty [35]

Answer:

f(x) = 0.43 * (x - 3)^{2}  * (x-1)^{3}*(x + 10)

Step-by-step explanation:

We have a 6th degree polynomial  f(x)

r = 3 is a root of f with multiplicity 2

r = 1 is a root of f with multiplicity 3

f(-5) = -29721.6

f(-10) = 0

Then:  f(x) = a*((x -3)^2 ) * ((x - 1)^3)*(x + 10)

f(-5) = a *  (-8)^2 *  (-6)^3  *  (5)  =  -29,721.6

a* (64) * (-216)* 5 = -29,721.6

-a*69,120 = -29,721.6

a =  -29,721.6/-69,120

a =  0.43

so

f(x) = 0.43 * (x - 3)^{2}  * (x-1)^{3}*(x + 10)

4 0
3 years ago
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