So you would get 5(x) and 5(-19)
So 5x and -95
So 5x-95
100/25= 4
9 out of 25 didnt like it
9 times 4= 36 didnt like it
100-36=64 like the book
SOLUTION: a 12 foot tree casts<span> a 16 </span>foot shadow<span>. How many </span>feet<span> tall is a nearby </span>tree<span> that casts a 20</span>foot shadow<span> at the same time ? Algebra -> Real-numbers -> SOLUTION: a </span>12 foot tree casts<span> a 16</span>foot shadow<span>. How many </span>feet<span> tall is a nearby </span>tree<span> that casts a 20 </span>foot shadow<span> at the same time</span>
Step-by-step explanation:
y=(2/5)x + 1
that is the answer
Given :
A 2.8 m ladder is to be laid against a wall so that the top of the ladder is 2 m up the wall.
To Find :
How far out from the base of the wall should the ladder be placed.
Solution :
We know, the angle between floor and height is 90° .
Now, length of ladder, l = 2.8 m .
Height of wall, h = 2 m .
Let, distance between base of the wall and ladder is b .
![l^2 = h^2 + b^2\\\\b = \sqrt{l^2 - h^2}\\\\b = \sqrt{2.8^2 - 2^2}\ m\\\\b = 1.96 \ m](https://tex.z-dn.net/?f=l%5E2%20%3D%20h%5E2%20%2B%20b%5E2%5C%5C%5C%5Cb%20%3D%20%5Csqrt%7Bl%5E2%20-%20h%5E2%7D%5C%5C%5C%5Cb%20%3D%20%5Csqrt%7B2.8%5E2%20-%202%5E2%7D%5C%20m%5C%5C%5C%5Cb%20%3D%201.96%20%5C%20m)
Hence, this is the required solution.