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elena-s [515]
3 years ago
6

If (4^a^-2)(4^3) = 64^2 , what is the value of a? a. 0 b. 4 c. 5 d. 7 e. 8

SAT
1 answer:
liraira [26]3 years ago
5 0

Answer:

\boxed{a=4}

Explanation:

Part 1. Finding product of (4a^2)(4^3)

Step 1. 4^3=64

Step 2. (4a^2) * (64) = (64 * 4)(a^2)

Step 3. (64 * 4)(a^2) = 256a^2

\boxed{(4a^{2})(4^3) = 256a^{2}}

Part 2. Simplifying the equation & solving for <em>a</em>

Step 1. \sqrt{256a^{2}} = \sqrt{64^{2}} ⇒ 16a = 64

Step 2. \frac{16a}{16} = \frac{64}{16}   (divide both sides by coefficient of variable)

\boxed{a = 4}

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Based on the information given bad debt expense is $8,675 and the journal entry is: Debit Bad debt  $6,575; Credit Allowance for Doubtful Account $6,575.

<h2>a. Bad debt expense:</h2>

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($8,675-$2,100)

Inconclusion bad debt expense is $8,675 and the journal entry is: Debit Bad debt  $6,575; Credit Allowance for Doubtful Account $6,575.

Learn more about bad debt expense here:brainly.com/question/24871617

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Given

P(A) = 0.61

P(A\ n\ B) = 0.39

Required

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P(A\ n\ B) = P(A) * P(B)

Substitute values for P(A) and P(A n B)

0.39 = 0.61 * P(B)

Make P(B) the subject

P(B) = \frac{0.39}{0.61}

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