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4 years ago

Refer to the equation 3×-2y=-18

Mathematics

2 answers:

Ksivusya [100]4 years ago

7 0

-2y÷2=y

3×y=-18

-3 -3

y=-21

Olin [163]4 years ago

7 0

<u><em>y=3 is the correct answer.</em></u> First you had to remove parenthesis first. And it gave us, $-3*2y=-18$ . Then multiply by the numbers. And it gave us, $-6y=-18$ . Next, divide by -6 from both sides of equation. And it gave us, $\frac{-6y}{-6}= \frac{-18}{-6}$ . And finally simplify, and it gave us the answer is y=3 is the right answer. Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie

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Enter your answer and show all the steps that you use to solve this problem in the space provided. Find the values of x and y.

satela [25.4K]

Answer : The value of x and y is, $90^o$ and $43^oC$

Step-by-step explanation :

First we have to calculate the angle B.

As we know that,

The given triangle is an isosceles triangle in which the angles opposite to equal sides are always equal.

Thus, $\angle B=\angle C$

Given : $\angle C=47^o$

$\angle B=\angle C=47^o$

$\angle B=47^o$

Now have to calculate the angle A.

As we know that the sum of interior angles of a triangle is equal to $180^o$ .

$\angle A+\angle B+\angle C=180^o$

$\angle A+47^o+47^o=180^o$

$\angle A+94^o=180^o$

$\angle A=180^o-94^o$

$\angle A=86^o$

Now we have to determine the angle y.

As we know that, line AD is an angle bisector. That means, it divides into two equal angles. So,

$\angle y=\frac{\angle A}{2}$

$\angle y=\frac{86^o}{2}$

$\angle y=43^o$

Now we have to determine the angle x.

As we know that the sum of interior angles of a triangle is equal to $180^o$ .

$\angle y+\angle B+\angle x=180^o$

$43^oc+47^o+\angle x=180^o$

$\angle x+90^o=180^o$

$\angle x=180^o-90^o$

$\angle x=90^o$

Thus, the value of x and y is, $90^o$ and $43^oC$

6 0

3 years ago

Which Two Numbers Add Up To Negative 26 And Multiply To 11?

Fynjy0 [20]

Xy=11
x+y=-26

x+y=-26
minus x both sides
y=-26-x

sub for y
x(-26-x)=11
-26x-x^2=11
add 26x+x^2 both sides
x^2+26x+11=0

ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

a=1
b=26
c=11

x= $\frac{-26+/-\sqrt{26^{2}-4(1)(11)} }{2(1)}$
x= $\frac{-26+/-\sqrt{676-44} }{2}$
x= $\frac{-26+/-\sqrt{632} }{2}$
x= $\frac{-26+/-2\sqrt{158} }{2}$
x= $-13+/-\sqrt{158}$

x= $-13+\sqrt{158}$ or $-13-\sqrt{158}$

aprox

x=-0.420195 or -25.5698

those are the numbers

5 0

3 years ago

What is the least common denominator of the rational expressions below? 1/x^2-5x+3/x^2+2x-35

Komok [63]

Here the denominators are quadratics , so we need to factorise them first

1/(x²-5x) +3/(x²+2x-35)

factorising x²-5x ,

here GCF is x, so taking x out we have

x(x-5)

factorising x²+2x-35 using AC method,

we find factors of -35 that add up to give 2

(x-5)(x+7)

Since we have x-5 common in both denominators, so lcd of the rational expression will be product of x(x-5)(x+7)

lcd is x(x-5)(x+7)

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3 years ago

HELP MATH PLEASE QUICK

yulyashka [42]

Answer:

15.7

Step-by-step explanation:

7 0

3 years ago

Help fast plz I need help with this

g100num [7]

4: 7,14,21,28,35
6: 10,8,6,4,2
8: 9,7,5,3,1

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3 years ago