Let's first determine the total number of the students.
=> 10 freshman
=>12 sophomores
=>15 juniors
<span>=> 30 seniors in the club. </span>
Since the adviser will only chose 1, let's add then divide by 4 to get the average.
=> 10 + 12 +15 + <span>30 = 67 students
</span>=> 67 / 4 = 16.75
OR close to
<span>=> 15/67</span>
The maximum height should be approximately 50.37 feet
A^3 because that would be a•a•a
Answer:
C. P= 1000M
Step-by-step explanation:
![log(\frac{M}{N} )=4](https://tex.z-dn.net/?f=log%28%5Cfrac%7BM%7D%7BN%7D%20%29%3D4)
Using the quotient rule of logs we can write:
log(M) - log(N) = 4
or
log(M) - 4 = log(N) (Equation 1)
![log(\frac{P}{N} )=4](https://tex.z-dn.net/?f=log%28%5Cfrac%7BP%7D%7BN%7D%20%29%3D4)
Using the quotient rule of logs we can write:
log(P) - log(N) = 7
or
log(P) - 7 = log(N) (Equation 2)
Comparing equation 1 and 2, we can write:
log(M) - 4 = log(P) - 7
-4 + 7 = log(P) - log(M)
log(P) - log(M) = 3
![log(\frac{P}{M} )=3](https://tex.z-dn.net/?f=log%28%5Cfrac%7BP%7D%7BM%7D%20%29%3D3)
Converting the log to exponential form we get:
![\frac{P}{M}=10^{3}\\\\\frac{P}{M}=1000\\\\P=1000M](https://tex.z-dn.net/?f=%5Cfrac%7BP%7D%7BM%7D%3D10%5E%7B3%7D%5C%5C%5C%5C%5Cfrac%7BP%7D%7BM%7D%3D1000%5C%5C%5C%5CP%3D1000M)
Thus, option C gives the correct answer.