Assume that when adults with smartphones are randomly selected, 49% use them in meetings or classes. If 14 adult smartphone us
ers are randomly selected, find the probability that fewer than 4 of them use their smartphones in meetings or classes.
1 answer:
Answer:
Probability of fewer than 4 = 0.0339
Explanation:
This is a question on binomial distribution. It is a distribution which has two possible outcome; a success or a failure
Probability of success (p) = 49%
Probability of failure (q) = 1 - 49% = 1-0.49
Probability of failure (q) = 0.51 = 51%
n = 14
P(X = x) = (n!)/[(n-x)!x!] × p^x × q^(n-x)
Probability of fewer than 4 = Pr(X <4)
Pr(X <4) = Pr(X = 0) + Pr(X = 1) +Pr(X = 2) +Pr(X = 3)
Find attached the workings
From the workings, Pr(X <4) = 0.0339295
Probability of fewer than 4 = 0.0339 (approximately)
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The parameters of the normal distribution of the thermometer readings are its mean and the standard deviation
The probability that a thermometer reading is between 99.86o F and 100.07o F is 0.5403
<h3>The sketch of the normal distribution of the thermometer</h3>The given parameters are:
- Mean, μ = 100
- Standard deviation, σ = 0.15
Next, we draw the normal distribution using a graphing calculator.
See attachment for the sketch of the normal distribution of the thermometer
<h3>The probability that a thermometer reading is between 99.86o F and 100.07o F</h3>This means that:
x = 99.86 and x = 100.07
The probability is calculated as:
P(99.86 < x < 100.07) = P(x > 99.86) - P(x < 100.07)
Using the attached graph, we have:
P(99.86 < x < 100.07) = 0.5403
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