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boyakko [2]
3 years ago
15

Which of these is a distinguishing abiotic feature of the Great Barrier Reef

Biology
2 answers:
Elanso [62]3 years ago
7 0
Apex answer is warm,shallow water
liubo4ka [24]3 years ago
5 0
<em>The Great Barrier Reef in Australia is known as the largest coral reef in the world and the largest living thing on Earth where it houses countless species of sea animals. </em>

Its distinguishing or distinct abiotic feature is its shallow waters.

Sunlight is one of the most important factors in an ecosystem necessary for the organism's survival. The reef mostly has shallow waters so it is easier for the light to penetrate the water for the organisms to use. Even the reefs are visible from the outer space due to its shallow waters. 

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Stem cells are important to multicellular organisms because of their
Lina20 [59]

Answer:

ability to differentiate into other cell types during cell division i.e. totipotent nature

Explanation:

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4 0
3 years ago
❥SCIENCE SUBJECT
Fiesta28 [93]

9514 1404 393

Answer:

  • time: 1.122 seconds
  • range: 10.693 m
  • maximum height: 1.543 m

Explanation:

<u>Given</u>:

  runner is launched at 30° angle to horizontal at 11 m/s

  acceleration due to gravity is g = -9.8 m/s²

<u>Find</u>:

  runner's hang time

  runner's distance to the landing point

  runner's maximum height

<u>Solution</u>:

The (horizontal, vertical) speed components will be ...

  (11 m/s)(cos(30°), sin(30°)) = (5.5√3 m/s, 5.5 m/s)

The time of flight can be found from the height formula:

  h(t) = 1/2gt² +vt . . . . . . where v is the vertical speed at launch

The time we're concerned with is the time when h(t)=0 and t>0.

  0 = -4.9t^2 +5.5√3t = t(-4.9t +5.5√3)

The second factor is zero when ...

  t = (5.5√3)/4.9 ≈ 1.122 . . . seconds hang time

__

The distance to the landing point will be the product of horizontal speed and hang time:

  d = (5.5 m/s)(5.5√3/4.9 s) ≈ 10.693 m . . . . distance to landing

__

The maximum height can be found from the formula (based on conversion of kinetic energy to potential energy) ...

  h = v²/|2g| = (5.5 m/s)²/(2(9.8 m/s²)) ≈ 1.543 m . . . . maximum height

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nika2105 [10]

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