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Elena-2011 [213]
3 years ago
13

A state park has two pools. The olympic size pool holds 8.12 x 105 gallons of water and the smaller pool holds 5.27 x 105 gallon

s of water. What is the combined capacity of the pools?
Mathematics
2 answers:
DochEvi [55]3 years ago
8 0

Answer:

The answer is is 1.339 x 106 gallons.

Step-by-step explanation:

The result is 13.39. This gives us 13.39 x 105 gallons. However, because the base must be greater than 1, but less than 10, we must move the decimal 1 place to the left which increases the exponent of 5 to 6.

mr_godi [17]3 years ago
6 0
First you need to work out what (8.12×105=?) Then (5.27×105=?) And add them together so (8.12×105)+(5.27×105)=the answer to your question
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Answer: Thursday

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<em>Answer:</em>

<em>8m</em>

<em>Step-by-step explanation:</em>

<em>We can convert the trapezium into a rectangle to make finding the area easier.</em>

<em>Say that the top side is 9m, and that the bottom side is 12m.</em>

<em>12 - 9 = 3</em>

<em>3/2* = 1.5</em>

<em>*Note that we are dividing by two to get the "overhang" of the bottom side.</em>

<em>Now that we have our overhang, we can find the length of the "t-rect"**.</em>

<em>**"T-rect" refers to a rectangle that has been formed by changing a trapezium into a rectangle.</em>

<em>12 - 1.5 = 10.5</em>

<em>9 + 1.5 = 10.5</em>

<em>The length of the t-rect is 10.5.</em>

<em>84/10.5 = 8</em>

<em>The height of the t-rect is 8m.</em>

<em>Since the height of the original trapezium is equal to the height of the t-rect***, </em>

<em>***Since we have only adjusted the length</em>

<em>this also means that 8m would also be the height of the original trapezium.</em>

<em>Now, there is a second way of doing this.</em>

<em>Find the median of 12 and 9.</em>

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<em>You get the same answer. These methods could be used as a solve-then-check method to another problem like these.</em>

<em>Hope this helps. Have a nice day.</em>

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Part 1) see the explanation

Part 2) see the explanation

Part 3) see the explanation

Part 4) see the explanation

Step-by-step explanation:

<u><em>The question in English is</em></u>

Read the situations and do the following with each one:

Write down the magnitudes involved

Write which magnitude is the independent variable and which is the dependent variable

It represents the function that describes the situation

SITUATIONS:

1) A machine prints 840 pages every 30 minutes.

2) An elevator takes 6 seconds to go up two floors.

3) A company rents a car at S/ 480 for 12 days.

4) 10 kilograms of papaya cost S/ 35

Part 1) we have

A machine prints 840 pages every 30 minutes

Let

x ----> the time in minutes (represent the variable independent or input value)

y ---> the number of pages that the machine print (represent the dependent variable or output value)

Remember that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In this problem

we have a a proportional variation

so

The value of the constant of proportionality is equal to

 k=\frac{y}{x}

we have

y=840\ pages\\x=30\ minutes

substitute

 k=\frac{840}{30}=28\ pages/minute

The linear equation is

y=28x

Part 2) we have

An elevator takes 6 seconds to go up two floors.

Let

x ----> the time in seconds (represent the variable independent or input value)

y ---> the number of floors (represent the dependent variable or output value)

Remember that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In this problem

we have a a proportional variation

so

The value of the constant of proportionality is equal to

 k=\frac{y}{x}

we have

y=2\ floors\\x=6\ seconds

substitute

 k=\frac{2}{6}=\frac{1}{3}\ floors/second

The linear equation is

y=\frac{1}{3}x

Part 3) we have

A company rents a car at S/ 480 for 12 days.

Let

x ----> the number of days (represent the variable independent or input value)

y ---> the cost of rent a car (represent the dependent variable or output value)

Remember that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In this problem

we have a a proportional variation

so

The value of the constant of proportionality is equal to

 k=\frac{y}{x}

we have

y=\$480\\x=12\ days

substitute

 k=\frac{480}{12}=\$40\ per\ day

The linear equation is

y=40x

Part 4) we have

10 kilograms of papaya cost S/ 35

Let

x ----> the kilograms of papaya (represent the variable independent or input value)

y ---> the cost  (represent the dependent variable or output value)

Remember that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In this problem

we have a a proportional variation

so

The value of the constant of proportionality is equal to

 k=\frac{y}{x}

we have

y=\$35\\x=10\ kg

substitute

 k=\frac{35}{10}=\$3.5\ per\ kg

The linear equation is

y=3.5x

6 0
3 years ago
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