The numbers go up in a linear fashion (by 1)
So, positive linear association
Answer:
read below
Step-by-step explanation:
Alright, archtan /
tan
−
1
(
x
)
is the inverse of tangent. Tan is
sin
cos
. Like the inverse of sin, the inverse of tan is also restricted to quadrants 1 and 4.
Knowing this we are solving for the inverse of tan -1. We are basically being asked the question what angle/radian does tan(-1) equal. Using the unit circle we can see that tan(1)= pi/4.
Since the "Odds and Evens Identity" states that tan(-x) = -tan(x). Tan(-1)= -pi/4.
Knowing that tan is negative in quadrants 2 and 4. the answer is in either of those two quadrants. BUT!!! since inverse of tan is restricted to quadrants 1 and 4 we are left with the only answer -pi/4.
the answer is m=-3n-5/2 or n=2m+5/6
The paragraph to show the comparision between two classes semester grades on the basis of the terms
- extremes
- quartiles
- medians
- ranges
is given below:
<h3>What is Box and Whisker plots?</h3>
A box and whisker plot is defined as a graphical method of displaying variation in a set of data.
From the first figure, write all the values where dark point is drawn
53, 62, 80, 86, 89
- The lower extreme is the smallest value, which is 53.
The upper extreme is the highest value, which is 89.
- The median will be the middle of data , which is 80
- The upper quartile is the median of the upper region and the lower quartile is the median of the lower region.
The upper quartile is 86 and the lower quartile is 62.
= Highest - Lowest
=89-53
=36
From the second figure, write all the values where dark point is drawn
56, 62, 74, 89, 96
- The lower extreme is the smallest value, which is 56.
The upper extreme is the highest value, which is 96.
- The median will be the middle of data , which is 74.
- The upper quartile is the median of the upper region and the lower quartile is the median of the lower region.
The upper quartile is 89 and the lower quartile is 62.
= Highest - Lowest
=96-62
=34
From the above discussion,
- The First class have less upper extreme value than the second class.
- The First class have less lower extreme value than the second class.
- The First class have greater median than the second class.
- The First class have less upper quartile than the second class.
- The First and second class have equal lower quartile.
- The First class have greater range than the second class.
The comparision of the two classes on the basis of extremes, quartile, median, range is concluded above.
learn more about box and whisper plot here:
brainly.com/question/11859288
#SPJ1
Answer: A good estimation would be about 150.
Step-by-step explanation:
To estimate we can round instead of using exact numbers.
First day he saw about 30 birds and twice as many squirrels, meaning about 60 squirrels. This is about 90 total when added together.
Second day he saw 20 birds and about 40 squirrels so about 60 when added together.
Add day one and day two totals for...
90+60=150
The formula for illuminance is given by
E = I / d^2
This formula only holds true for one-dimensional illuminance
The problem asks for the illuminance across the floor. We need to use two variables, x and y.
From Pythagorean Theorem
d^2 = x^2 + y^2
and from Trigonometry
x = d cos t
y = d sin t
The function for the illuminance can be represented by the composite function
E = I cos² t / x²
and
E = I sin² t / y²
The boundary of these functions is:
<span>0 < t < 8
So, the value of t must be in radians and not in degrees</span>
