1. The shape of cross-section is a circle.
2. The face parallel to ABCD is EFGH. Since this is a a rectangular shape,
A = L*H = 12*6 = 72 cm^2
3. The cross-section parallel to ABC is DEF with h = 12 ft, b= 5ft (where h is the height and b is the base of a right angled triangle).
Area, A = 1/2 *b*h = 1/2*5*12 =30 ft^2
4. Plane BDHF is a rectangle shape whose length is the diagonal of ABCD.
Diagonal BD = sqrt (AB^2+BD^2) = sqrt (8^2+7^2) = 10.63 cm.
Perimeter, P = 2(BD+DH) = 2(10.63+6) = 33.26 cm
To find the value of x we first need to find the missing angle in the triangle.
To do that we are gonna add the angles we already have.
64 + 45 = 109
Angles in a triangle measures 180 so to get the missing angle we are gonna subtract 109 from 180
180 - 109 = 71 deg
The missing angle in the triangle is 71 deg
Angles on a straight line adds up to 10 so to find x we are gonna subtract 71 from 180
180 - 71 = 109 degrees
Therefore x is 109 degrees.
I just took the test and the answer was D
50 in, 48 in, 14 in are the side lengths that form a right triangle
Answer:
I think this could be the answer- x^ +2x-15
I think the answer is
x < (2b -8) / 3
or
x < 2b/3 - 8/3
