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Alona [7]
3 years ago
7

Rene has secured her wireless network. However, she is worried about securing her router against newfound vulnerabilities. Which

is the best method that Rene can employ?
A.switching over to wired network
B.making minimal use of the wireless network
C.refrain from changing the SSID
D.regularly updating firmware
Computers and Technology
1 answer:
Fynjy0 [20]3 years ago
4 0
It is C I have a lot of experience with computers and technology
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The organization must develop it specifically for the business in order to get the functionality required is True.

a) true

<u>Explanation:</u>

In software development industry it called as EAS. Where organizations required complete one solution and made most customizable with less cost effective.

Moreover to implement the same organizations has to spend less money for software development and hardware appliances. An organization has clear documented which specific their business requirements and their business future expansion.

Basically in organization from low grade employee to higher employee and meeting is arranged and understand system requirements and compiled as document which is circulated to higher official in organization for their final approval.

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Borrowers taking a balloon payment mortgage most likely plan to rent out their homes. must repay the loan in five to ten years.
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Borrowers taking a balloon payment mortgage most likely "<span>must repay the loan in five to ten years".
</span>

<span>B<span>alloon payment refers to a fixed amount of money connected to a loan someone takes; this sum has a greater value than the actual repayment costs and can be applied at fixed periods of time at the end. </span>It can run for longer periods as well.</span>

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4 years ago
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Team members support one another when they view differences as being? A) annoyances they can live with B) signs of poor training
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C (dont mind this sentence it is so that i can reach 20 characteristics)




























                                          
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Case-Based Critical Thinking Questions Case 1-2 Ted is asked to create a page containing his family photos for a family reunion
Vera_Pavlovna [14]

Answer:

Image tag or <img> tag

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HTML refers to Hypertext Markup language. In this, we can be designed our documents by applying the font, color, image i.e to presented in the web browser. It is used for creating the webpages

Since in the question, Ted has approx 20 pictures for the post having caption and wants to display the picture so he needs to use the image tag or <img> for displaying the pictures. This tag is used for linking the images for the web pages you have created

7 0
3 years ago
Complete the method, longestWord(), below that takes in an array of Strings and returns the longest String in the array. Note: y
beks73 [17]

Answer:

I am writing a JAVA program.

public class StringMethod {

public static String longestWord(String []words) { //method that takes an array  "word" of strings and returns the longest string in the array word

    int pos = 0; // contains index of the longest word of array words

    int longest = words[0].length(); //initially holds the length of the 1st element of words array

    for(int i=1; i< words.length; i++) { // iterates through each word of the array until the end of array

        if(words[i].length() > longest) { // if the length of word at i-th index of words[] is greater than the length of the word that is contained in longest variable

            pos = i; // assigns the index of the longest array element to pos

            longest = words[i].length();    } } //assigns the word in words[] array with the longest length to longest variable

   return words[pos]; } // returns the longest string in the array    

public static void main(String[] args) { //start of main() function body

String[] animals = {"cat", "horse", "elephant", "bird"}; //creates a String type array named animals which has 4 elements/words

   String longest_word= longestWord(animals); //calls longestWord method to find the longest string in the array animals and assign that longest string to longest_word.

  System.out.println(longest_word); }} //displays the longest word in output

Explanation:

Suppose we have the array of these elements: "cat", "horse", "elephant", "bird" These are four words in the array. Now lets see how the method longestWord() works:

int pos = 0; This variable is initialized to 0.

int longest = words[0].length();

longest holds the length of element at 0th index of words[] array. length() method is used to return the length of the first element words[0] array.

As the first element of array is "cat" so length of cat is 3. Hence longest = 3

for(int i=1; i< words.length; i++)

The loop has a variable i which is initialized to 1. The loop checks if the value of i is less than length of words[] array. The length of words array is 4 as there are 4 elements i.e. cat, horse, elephant and bird in this array. So the condition evaluates to true because i<words.length i.e. 1<4. The body of the loop will execute now. The body of loop contains an if condition if(words[i].length() > longest) which checks if the length of element of array at i-th index is greater than length of the element that is stored in longest variable. As i=1 so word[i] is word[1] which is the second element of words[] array. The second element is horse.

words[i].length()  means the length of i-th element of words[] array. So this means words[1].length() i.e. the length of element of words[] at 1st index. The length of horse is 5. So the statement if(words[i].length() > longest) is true because longest=3 and words[1].length() = 5 and 5>3. So the statements of if condition will execute now.

pos = i; this variable pos is used to hold the index position of the longest element in array. So pos = 1 as longest element computed so far is "horse".

longest = words[i].length(); This statement then assigns the length of horse to longest. So now the value of longest = 5

At second iteration i is now 2.  Loop condition evaluates to true because i<words.length i.e. 2<4. If condition is also true as i=2 so word[i] is word[2] which is elephant.

words[i].length() now means words[2].length() i.e. the length of element of words[] at 2nd index. The length of elephant is 8. So the statement if(words[i].length() > longest) is true because longest=5 and words[2].length() = 8 and 8>5. So the statements of if condition will execute now.

pos = i; now becomes pos = 2 as longest element computed so far is "elephant".

longest = words[i].length();  This statement then assigns the length of horse to longest. So now the value of longest = 8

At third iteration i is now 3.  The loop again checks if the value of i is less than length of words[] array.The condition evaluates to true because i<words.length i.e. 3<4. The body of the loop will execute now.  if(words[i].length() > longest) checks if the length of element of array at i-th index is greater than length of the element that is stored in longest variable. As i=3 so word[i] is word[3] which is the fourth element of words[] array. The fourth element is bird.

words[i].length() now means words[3].length() i.e. the length of element of words[] at 3rd index. The length of bird is 4. So the statement if(words[i].length() > longest) is false because longest=8 and words[2].length() = 4 and 4<8. So the statements of if condition will not execute now.

At fourth iteration i is now 4.  The loop again checks if the value of i is less than length of words[] array.The condition evaluates to false because i==words.length i.e. 4=4. So the loop breaks.

 return words[pos]; statement returns the index position of longest word in words[] array. pos = 2 So the array element at 2nd index is basically the third element of array words[] i.e. elephant. So the longest string in the array is elephant.

8 0
3 years ago
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