Question

A chef cooked 5 kilograms of mashed potatoes for a dinner party. If the guests only ate 4/12 of the amount he cooked, how much did they eat?

Answer 1

Answer:

$1\frac{2}{3}\ kg$

Step-by-step explanation:

we know that

To find out how much the guests ate, multiply the total amount of kg of mashed potatoes by the 4/12 fraction

so

$5(\frac{4}{12})=\frac{20}{12}\ kg$

convert to mixed number

$\frac{20}{12}=\frac{12}{12}+\frac{8}{12}=1\frac{8}{12}\ kg$

simplify

$1\frac{8}{12}=1\frac{2}{3}\ kg$