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Artemon [7]
4 years ago
15

Which expression is equivalent to cot t sec t?

Mathematics
2 answers:
const2013 [10]4 years ago
5 0
\cot t \sec t=\dfrac{\cos t}{\sin t}\cdot\dfrac{1}{\cos t}=\dfrac{1}{\sin t}=\csc t
Alenkinab [10]4 years ago
4 0
The answer is "A" "csc t"
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Help!! Im stuck on this!
Mila [183]

Answer:

when doing questions like these you need to do pemdas and do it in order

Step-by-step explanation:

p- parenthesis

e- exponents

m- multipication

d- division

a- adding

s- subtracting

5 0
3 years ago
Sequences and series
Vinvika [58]

Answer:

D

Step-by-step explanation:

a_{n}=\frac{(n+3)!}{(n+3}=\frac{(n+3)(n+2)!}{n+3}=(n+2)!\\a_{1}=(1+2)!=3!=3*2*1=6\\a_{2}=(2+2)!=4!=4*3*2*1=24\\a_{3}=(3+2)=5!=5*4!=5*24=120\\a_{4}=(4=2)!=6!=6*5!=120*6=720\\a_{5}=(5+2)=7!=7*6!=720*7=5040

5 0
3 years ago
Container R holds a solution that is 20% alcohol and Container S holds a solution that is 60% alcohol. How many liters of soluti
Nikolay [14]

Answer:

The number of liters for container R = x = 0.5 liters

The number of liters for container S = y = 1.5 liters.

Step-by-step explanation:

Let the number of liters of container R = x

Let the number of liters of container S = y

We are told in the question : that

Container R holds a solution that is 20% alcohol

= 20% × x = 0.20x

Container S holds a solution that is 60% alcohol.

= 60% × y = 0.60y

How many liters of solution from each container should be used to create 2 liters of solution that is 50% alcohol?

Hence;

x + y = 2 ....... Equation 1

x = 2 - y

0.20x + 0.60y = 2 × 50%

0.20x + 0.60y = 1........ Equation 2

Substitute

2-y for x in Equation 3

0.20(2 - y) + 0.60y = 1

0.40 - 0.20y + 0.60y = 1

Collect like terms

0.40y = 1 - 0.40

0.40y = 0.60

y = 0.60/0.40

y = 1.5 liters

Note that :

x = 2 - y

x = 2 - 1.5

x = 0.5 liters

Therefore,

the number of liters for container R = x = 0.5 liters

the number of liters for container S = y = 1.5 liters.

5 0
3 years ago
PLS HELP WILL GIVE BRAINLIEST
andreyandreev [35.5K]

The guts of the table are ...

\left[\begin{array}{cccc}x&y&x+y=85&y=2x+4\\19&65&\text{false}&\text{false}\\25&60&\text{true}&\text{false}\\27&58&\text{true}&\text{true}\\32&53&\text{true}&\text{false}\end{array}\right]

Of course, you know the answer after figuring the third line of the table.

The two numbers are 27 and 58.

_____

If the second number is odd, the result after subtracting 4 will not be divisible by 2. This lets you reject the 1st and 4th choices immediately. As for the second choice, twice 25 is 10 less than 60, not 4 less, so that choice can also be discarded.

Starting from the system of equations

x+y=85\\y=2x+4

you can use substitution to get

x+(2x+4)=85\\\\3x=81\qquad\text{subtract 4}\\\\x=27\qquad\text{divide by 3}

This identifies the 3rd selection as the appropriate one.

5 0
3 years ago
Read 2 more answers
Please answer, working out pls
elena-s [515]
The picture is cropped, i can't see the question written. Maybe you should send another picture .
7 0
4 years ago
Read 2 more answers
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