Answer:
when doing questions like these you need to do pemdas and do it in order
Step-by-step explanation:
p- parenthesis
e- exponents
m- multipication
d- division
a- adding
s- subtracting
Answer:
D
Step-by-step explanation:

Answer:
The number of liters for container R = x = 0.5 liters
The number of liters for container S = y = 1.5 liters.
Step-by-step explanation:
Let the number of liters of container R = x
Let the number of liters of container S = y
We are told in the question : that
Container R holds a solution that is 20% alcohol
= 20% × x = 0.20x
Container S holds a solution that is 60% alcohol.
= 60% × y = 0.60y
How many liters of solution from each container should be used to create 2 liters of solution that is 50% alcohol?
Hence;
x + y = 2 ....... Equation 1
x = 2 - y
0.20x + 0.60y = 2 × 50%
0.20x + 0.60y = 1........ Equation 2
Substitute
2-y for x in Equation 3
0.20(2 - y) + 0.60y = 1
0.40 - 0.20y + 0.60y = 1
Collect like terms
0.40y = 1 - 0.40
0.40y = 0.60
y = 0.60/0.40
y = 1.5 liters
Note that :
x = 2 - y
x = 2 - 1.5
x = 0.5 liters
Therefore,
the number of liters for container R = x = 0.5 liters
the number of liters for container S = y = 1.5 liters.
The guts of the table are ...
![\left[\begin{array}{cccc}x&y&x+y=85&y=2x+4\\19&65&\text{false}&\text{false}\\25&60&\text{true}&\text{false}\\27&58&\text{true}&\text{true}\\32&53&\text{true}&\text{false}\end{array}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7Dx%26y%26x%2By%3D85%26y%3D2x%2B4%5C%5C19%2665%26%5Ctext%7Bfalse%7D%26%5Ctext%7Bfalse%7D%5C%5C25%2660%26%5Ctext%7Btrue%7D%26%5Ctext%7Bfalse%7D%5C%5C27%2658%26%5Ctext%7Btrue%7D%26%5Ctext%7Btrue%7D%5C%5C32%2653%26%5Ctext%7Btrue%7D%26%5Ctext%7Bfalse%7D%5Cend%7Barray%7D%5Cright%5D%20%20)
Of course, you know the answer after figuring the third line of the table.
The two numbers are 27 and 58.
_____
If the second number is odd, the result after subtracting 4 will not be divisible by 2. This lets you reject the 1st and 4th choices immediately. As for the second choice, twice 25 is 10 less than 60, not 4 less, so that choice can also be discarded.
Starting from the system of equations

you can use substitution to get

This identifies the 3rd selection as the appropriate one.
The picture is cropped, i can't see the question written. Maybe you should send another picture .