Answer:
![(g\circ h)(x)=-x^2-x-3](https://tex.z-dn.net/?f=%28g%5Ccirc%20h%29%28x%29%3D-x%5E2-x-3)
Step-by-step explanation:
So we have the two functions:
![g(x)=-x-3\text{ and } h(x)=x^2+x](https://tex.z-dn.net/?f=g%28x%29%3D-x-3%5Ctext%7B%20and%20%7D%20h%28x%29%3Dx%5E2%2Bx)
And we want to find:
![(g\circ h)(x)](https://tex.z-dn.net/?f=%28g%5Ccirc%20h%29%28x%29)
This is the same thing as:
![=g(h(x))](https://tex.z-dn.net/?f=%3Dg%28h%28x%29%29)
So, substitute h(x) into g(x):
![g(x)=-x-3\\g(h(x))=-(x^2+x)-3](https://tex.z-dn.net/?f=g%28x%29%3D-x-3%5C%5Cg%28h%28x%29%29%3D-%28x%5E2%2Bx%29-3)
Distribute the negative:
![g(h(x))=-x^2-x-3](https://tex.z-dn.net/?f=g%28h%28x%29%29%3D-x%5E2-x-3)
And we're done!
So:
![(g\circ h)(x)=-x^2-x-3](https://tex.z-dn.net/?f=%28g%5Ccirc%20h%29%28x%29%3D-x%5E2-x-3)
Answer:
B
Step-by-step explanation:
it matches the table
Answer:Do you have a pic of the map? It would make it easier to solve if I could see the map. Its basic area. A=base times height. If the park is 50 m long and is a square, you would do 50 times 50=2500
tep-by-step explanation:
Answer:
53 minutes
Step-by-step explanation:
Let x be the time required for a full video upload. This would have the unit of (minutes/full upload). Since the upload rate is constant, we can write:
(0.17)*(x) = 9 minutes
This equation states that 17% of the full upload time is 9 minutes.
Solve for x:
x = (9 minutes)/(0.17)
x = 52.9 minutes or 53 minutes with 2 sig figs