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Tems11 [23]
3 years ago
13

50 POINTSwhat is 2^-4×r^3×s^-2 when r=-3 and s=5?Explain please..

Mathematics
2 answers:
Korvikt [17]3 years ago
5 0
You'll get -6.25
To find a negative power, put it 1 over it and remove the negative symbol. For example, to simplify 2^-4, we would do 1/2^-4, then remove the negative to get 1/2^4, which is 0.0625
Then you have that -3^3 is -27 (since -3*-3*-3 is -27). Then using the above method, you can simplify 5^-2 to 1/5^2, which is 0.4

0.0625*-27*0.4 is -27/400

:)
lesya [120]3 years ago
4 0
2⁻⁴ * r³ * s⁻² = r³ / (s⁴ * s²) = 1 / (2 * 2 * 2 * 2) * (r * r * r) * 1 / (s * s)

2^{-4}* r^{3} *s^{-2} =  \frac{ r^{3} }{ 2^{4} * s^{2} } =  \frac{r*r*r}{2*2*2*2*s*s}
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