Question

50 POINTSwhat is 2^-4×r^3×s^-2 when r=-3 and s=5?Explain please..

Answer 1

You'll get -6.25
To find a negative power, put it 1 over it and remove the negative symbol. For example, to simplify 2^-4, we would do 1/2^-4, then remove the negative to get 1/2^4, which is 0.0625
Then you have that -3^3 is -27 (since -3*-3*-3 is -27). Then using the above method, you can simplify 5^-2 to 1/5^2, which is 0.4

0.0625*-27*0.4 is -27/400

:)

Answer 2

2⁻⁴ * r³ * s⁻² = r³ / (s⁴ * s²) = 1 / (2 * 2 * 2 * 2) * (r * r * r) * 1 / (s * s)

$2^{-4}* r^{3} *s^{-2} = \frac{ r^{3} }{ 2^{4} * s^{2} } = \frac{r*r*r}{2*2*2*2*s*s}$