Answer:
First, second, and fifth.
Step-by-step explanation:
I already did the test.
Since there is an expression in the square root, it must be non-negative. So:
Then, the interval is:
![\boxed{x\in~]-\infty,4]}](https://tex.z-dn.net/?f=%20%5Cboxed%7Bx%5Cin~%5D-%5Cinfty%2C4%5D%7D)
Answer:
m<5 = 142
Step-by-step explanation:
Answer:
a) e-0.03x(0.3-0.009x)
b) 33 hrs 20 min
c) 17.182
Step-by-step explanation:
Taking derivative of the above equation would give us the rate for change in donations :
hence
f'(x) = d/dx (0.3xe-0.03x)
using product rule of derivation where (uv)' = u'v +v'u
hence
f'(x) = (e-0.03x)d/dx(0.3x) + 0.3x*d/dx(e-0.03x)
= 0.3e-0.03x + 0.3x(-0.03)(e-0.03x)
f'(x) =0.3e-0.03x -0.009xe-0.03x
hence
a) rate of change in donations = e-0.03x(0.3-0.009x) taking exponent common
b) f'(x) = 0 according to statement
hence 0 = e-0.03x(0.3-0.009x)
0 = 0.3 - 0.009 x
which gives x = 33.33 hrs i.e after 33 hrs and 20 minutes rate of change of donations is 0.
c) donation level at the time is given by
f(x) = 0.3xe-0.03x
f(33.33) = 0.3 (33.33)e-0.03(33.33)
= 17.182
That is 17.182 thousand donations were made at that time.
