Given:
Tangent segment MN = 6
External segment NQ = 4
Secant segment NP =x + 4
To find:
The length of line segment PQ.
Solution:
Property of tangent and secant segment:
If a secant and a tangent intersect outside a circle, then the product of the secant segment and external segment is equal to the product of the tangent segment.



Subtract 16 from both sides.


Divide by 4 on both sides.


The length of line segment PQ is 5 units.
The 4 on the left side is 10x more than the 4 on the right. This only works if the numbers are next to each other and are the same.
Answer:
Here, answer is given in form of 4 figure labelled with inequality
Step-by-step explanation:
Given inequality are
A). 
B). 
C). 
D). 
For matching with givens graph:
Simplifying...
A). 
Divide 2 on both sides

B). 
Add (-6) on both side.


C). 
Add (4) on both side.


D). 
Multiple (-1) on both side

Note : Change of inequality sign due to multipication of negative number
Add (-5) on both side.

Here, Answer is given in form of 4 figure labelled with inequality
Answer:
a.) 
b.)

Step-by-step explanation:
a.) We are given the heights and their frequency. We can make a new set:
198, 199, 199, 199, 200, 200, 201, 201, 201, 201, 201, 202, 202
Now find the mean. The mean is found by adding all the numbers in the set, then dividing the total by the number of terms in the set. Add:

Now count the terms. There are 13 terms. Divide the total by the number of terms:

The mean is 200.3.
b.) Use random values like 200, 198 etc. and add them to the total of the last set, then divide by 14 instead of 13 (because there is a new player). Do this until you get a mean of 201 with the new height:

For the new mean to be 201 cm, the new player has a height of 210 cm.
Finito.