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sertanlavr [38]

3 years ago

14

A random sample of 200 adults are classified below by sex and their level of education attained. Education Male Female Elementar

y 36 47 Secondary 26 52 College 20 19 If a person is picked at random from this group, find the probability that (
a. the person is a male, given that the person has a secondary education (
b. the person does not have a college degree, given that the person is a female

1 answer:

borishaifa [10]3 years ago

7 0

Solution:

a. the person is a male, given that the person has a secondary education.

The probability that a person is a male, given that the person has secondary education is:

P(Male | Secondary education) $=\frac{26}{78}=\frac{1}{3}$

Therefore, a person is a male, given that the person has secondary education is $\frac{1}{3}$

b. The person does not have a college degree, given that the person is a female.

The probability that a person does not have a college degree, given that the person is a female is:

P(Not college degree | female) $=\frac{47+52}{118}=\frac{99}{118}$

Therefore, a person does not have a college degree, given that the person is a female is $\frac{99}{118}$

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Troyanec [42]

Answer: Volume = $\frac{20\pi }{3}$

Step-by-step explanation: The <u>washer</u> <u>method</u> is a method to determine volume of a solid formed by revolving a region created by any 2 functions about an axis. The general formula for the method will be

V = $\pi \int\limits^a_b {(R(x))^{2} - (r(x))^{2}} \, dx$

For this case, the region generated by the conditions proposed above is shown in the attachment.

Because it is revolting around the y-axis, the formula will be:

$V=\pi \int\limits^a_b {(R(y))^{2} - (r(y))^{2}} \, dy$

Since it is given points, first find the function for points (3,2) and (1,0):

m = $\frac{2-0}{3-1}$ = 1

$y-y_{0} = m(x-x_{0})$

y - 0 = 1(x-1)

y = x - 1

As it is rotating around y:

x = y + 1

This is R(y).

r(y) = 1, the lower limit of the region.

The volume will be calculated as:

$V = \pi \int\limits^2_0 {[(y+1)^{2} - 1^{2}]} \, dy$

$V = \pi \int\limits^2_0 {y^{2}+2y+1 - 1} \, dy$

$V=\pi \int\limits^2_0 {y^{2}+2y} \, dy$

$V=\pi(\frac{y^{3}}{3}+y^{2} )$

$V=\pi (\frac{2^{3}}{3}+2^{2} - 0)$

$V=\frac{20\pi }{3}$

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4 years ago

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Answer:

The work done in stretching it from its natural length to 14 in. beyond its natural length is W=8.17 ft-lb.

Step-by-step explanation:

We know that a force of 8 lb is required to hold a spring stretched 8 in. beyond its natural length.

This let us calculate the spring constant k as:

$F=kx\\\\k=F/x=(8 \;lb)/(8\;in)=1\;lb/in$

We know that work is, in an scalar form, the product of force and distance.

The force F is equal to the spring constant multiplied by the distance from the natural length.

Then, as the force changes with the distance from the natural length, we have to calculate integrating:

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Dmitriy789 [7]

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Step-by-step explanation:

P.S - The exact question is -

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