Find the distance from the point to the given plane. (−8, 7, 6), x − 2y − 4z = 8

1 answer:

3 0

The formula for the distance from a point (x, y, z) to the plane ax +by +cz +d = 0 is this:
.. distance = |ax +by +cz +d|/√(a^2 +b^2 +c^2)

For your point and plane, that is
.. distance = |-8 -2*7 -4*6 -8|/√(1^2 +2^2 +4^2)
.. = 54/√21
.. = (18/7)√21

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Hope this Helps!!!!