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3 years ago

12

Which expdession is equivalent to 4-2(3x-5)

1 answer:

GalinKa [24]3 years ago

7 0

Answer:

4

Step-by-step explanation:

Your answer would be 0 because you have to subtract 3 by 5 you get the answer 2. Then you subtract 4 by 2 and you 2. After that you multiply 2 by 2 getting the answer 4.

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A triangle has sides with lengths of 65 in 72 in and 97 in is it a right triangle?

Ray Of Light [21]

Answer:

yes

Step-by-step explanation:

By pythagoras' theorem,

97^2 = 9409

65^2 + 72^2 = 9409

since 65^2 + 72^2 = 97^2, the triangle is a right angled triangle

This is a question on Pythagoras theorem. If you wish to venture further into it/understand this topic better, you may want to follow my Instagram account (learntionary), where I post some of my own notes on certain topics and also some tips that may be useful to you :)

6 0

2 years ago

A collrollary is a statement that can easily provide using a theorem

DedPeter [7]

Im Guessing this is a true and fasle

So the answer would be False

5 0

3 years ago

Hi, how's everyone doing? I need help with these exponential equations, please. Thanks! :)

Vesna [10]

Answer:

Step-by-step explanation:

1). $2^{x^{2} +2x}=\frac{1}{2}$

$2^{x^{2} +2x}=2^{-1}$

Comparing exponents on both the sides.

x² + 2x = -1

x² + 2x + 1 = 0

(x + 1)² = 0

x = -1

2). $2^{x-3}=8^{x+1}$

$2^{x-3}=(2^{3})^{x+1}$

$2^{x-3}=(2)^{3(x+1)}$

By comparing exponents,

x - 3 = 3(x + 1)

x - 3 = 3x + 3

3x - x = 3 + 3

2x = 6

x = 3

3). $\sqrt{a^{5-k}}=a^{3-k}$

$a^{\frac{5-k}{2}}=a^{3-k}$

By comparing exponents,

$\frac{5-k}{2}=3-k$

5 - k = 2(3 - k)

5 - k = 6 - 2k

2k - k = 6 - 5

k = 1

4). $3^{x+3}=27^{(2x+6)}$

$3^{x+3}=(3^3)^{2x+6}$

$3^{x+3}=(3)^{3(2x+6)}$

By comparing exponents,

x + 3 = 3(2x + 6)

x + 3 = 6x + 18

6x - x = 3 - 18

5x = - 15

x = -3

5). $5^{x-2}=1$

$5^{(x-2)}=5^{0}$

x - 2 = 0

x = 2

6 0

3 years ago

How do I even start this? And how to i order the equation to solve

Kobotan [32]

$f(g(h(x)))=f(g(\sqrt x))=f(\sqrt x-1)=\boxed{(\sqrt x-1)^4+4}$

This is because

$h(x)=\sqrt x$

$g(x)=x-1$

$\implies g(h(x))=\sqrt x-1$

(that is, replace any instance of <em>x</em> in the definition of <em>g</em> with √<em>x</em> )

and

$f(x)=x^4+4$

$\implies f(\sqrt x-1)=(\sqrt x-1)^4+4$

(replace any <em>x</em> in <em>f</em> with √<em>x</em> - 1)

Also acceptable:

$(\sqrt x-1)^4+4=((\sqrt x)^4-4(\sqrt x)^3+6(\sqrt x)^2-4\sqrt x+1)+4$

$=\boxed{x^2-4x\sqrt x+6x-4\sqrt x+5}$

(assuming <em>x</em> is not negative)

6 0

2 years ago

Find each difference. Write in simplest form. <br> 3 4/6 - 1 5/6=

kodGreya [7K]

Answer:

1 5/6

Step-by-step explanation:

Turn the mixed fractions into improper fractions

3 4/6 = 22/6 and 1 5/6 = 11/6

Do the subtraction

22/6 - 11/6 = 11/6 or 1 5/6.

4 0

2 years ago

Read 2 more answers