Answer will be 1 because it’s by its self or it could be 2
Step-by-step explanation:
Note: Question does not indicate if probability required is for weight to exceed or below 3000 lbs. So choose appropriate answer accordingly (near the end)
Using the usual notations and formulas,
mean, mu = 3550
standard deviation, sigma = 870
Observed value, X = 3000
We calculate
Z = (X-mu)/sigma = (3000-3550)/870 = -0.6321839
Probability of weight below 3000 lbs
= P(X<3000) = P(z<Z) = P(z<-0.6321839) = 0.2636334
Answer:
Probability that a car randomly selected is less than 3000
= P(X<3000) = 0.2636 (to 4 decimals)
Probability that a car randomly selected is greater than 3000
= 1 - P(X<3000) = 1 - 0.2636 (to 4 decimals) = 0.7364 (to 4 decimals)
Placing the new question at the start or at the end of the
test will definitely invalidate the accuracy of the data. This is because the 1st
and the last questions are the most noticeable part in a given set. Therefore the
answer to this question is that “The Company should randomly introduce the new
question type among other questions in the test”.
Answer:
$12.60 per hour
Step-by-step explanation:
5% of 12 is 0.60
12 + 0.60 = 12.60
