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vagabundo [1.1K]
3 years ago
11

What is the value of StartFraction negative 2 (7 minus 15) over 4 EndFraction? –4 –2 2 4

Mathematics
2 answers:
maw [93]3 years ago
7 0

Answer:

D

Step-by-step explanation:

I TOOK the test

BartSMP [9]3 years ago
3 0

Answer:

The Correct answer is last option i.e 4.

Therefore,

-2(\dfrac{7-15}{4})=4

Step-by-step explanation:

Given:

StartFraction negative 2 (7 minus 15) over 4 EndFraction

Means

-2(\dfrac{7-15}{4})

-2(\dfrac{-8}{4})

-2(-2)

Minus sign will enter in it and ( - ) × ( - ) = ( + )

4

Therefore,

-2(\dfrac{7-15}{4})=4

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Alina [70]

Answer:

r=56

Step-by-step explanation:

252= r * 4.5

r * 4.5 = 252

r * 4.5 * 10 = 252 * 10

45r = 2520

r = 56

6 0
4 years ago
According to a Los Angeles Times study of more than 1 million medical dispatches from to , the response time for medical aid var
-BARSIC- [3]

Answer:

A)Mean :10.65

Median =10.7

Mode : 10.7

B)Range = 3.5

Standard deviation :0.89916

C)The response time of 8.3 minutes should be considered an outlier in comparison to the other response times

Step-by-step explanation:

A)

Data : 11.8 ,10.3, 10.7, 10.6, 11.5, 8.3, 10.5, 10.9, 10.7, 11.2

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\Mean = \frac{11.8 +10.3+ 10.7+ 10.6+ 11.5+ 8.3+ 10.5+ 10.9+ 10.7+ 11.2}{10}

Mean = 10.65

Median: The mid value of the data

Data in ascending order

8.3

10.3

10.5

10.6

10.7

10.7

10.9

11.2

11.5

11.8

n=10(even)

Median = \frac{(\frac{n}{2})\text{th term}+(\frac{n}{2}+1)\text{th term}}{2}\\Median = \frac{(\frac{10}{2})\text{th term}+(\frac{10}{2}+1)\text{th term}}{2}\\Median = \frac{10.7+10.7}{2}\\Median = 10.7

Mode : the most occurring frequency

10.7 is occurring twice while others are occurring once

So, Mode is 10.7

B) Range = Maximum - Minimum=11.8-8.3=3.5

Standard deviation : \sqrt{\frac{\sum(x-\bar{x})^2}{n}}

Standard deviation :\sqrt{\frac{(11.8-10.65)^2+(10.3-10.65)^2+......+(10.9-10.65)^2+(10.7-10.65)^2+(11.2-10.65)^2}{10}}

Standard deviation :0.89916

C)

8.3

,10.3

,10.5

,10.6

,10.7

,10.7

,10.9

,11.2

,11.5

,11.8

For Q1 ( Median of lower quartile )

8.3

,10.3

,10.5

,10.6

,10.7

Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=10.5

For Q3( Median of Upper quartile )

10.7

,10.9

,11.2

,11.5

,11.8

Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=11.2

IQR = Q3-Q1=11.2-10.5=0.7

Range :(Q1-1.5IQR, Q3-1.5IQR)

Range :(10.5-1.5 \times 0.7, 11.2-1.5 \times 0.7)

Range :(9.45, 10.15)

8.3 does not lie in this interval

So, the response time of 8.3 minutes should be considered an outlier in comparison to the other response times

3 0
3 years ago
Help me wit this pls do now
Anna [14]

Answer:

  see below

Step-by-step explanation:

If x represents the number of dimes, then 2x will represent twice the number of dimes. This is the number of quarters, since there are twice as many quarters as dimes.

There are 6 more nickels than dimes, so the number of nickels is 6 more than x. It is (x+6).

If we use the monetary values in cents, then the total of all coins is ...

  25(2x) +10(x) + 5(x+6) = 485 . . . . . . matches choice D

4 0
3 years ago
Caleb placed 3 yellow balls and 4 red balls in a row.
qwelly [4]

Answer:

I think it's C)144. because I think it's C

6 0
2 years ago
Is (5, 4) a solution to this system of equations?<br> 2x + 3y = 23 <br> y + x = 9
lions [1.4K]
No because it works for y + x= 9 but not the first one
6 0
3 years ago
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