Explanation:
. use reusable bags
. print as little as necessary
. recycle
. save electricity
Complete question:
Which organisms are secondary consumers in a temperate coniferous forest? Select all that apply:
Answer:
The lynx and the wolf are the only secondary consumers on the list.
Explanation:
In the trophic web, the energy transference occurs when each organism feeds on the preceding link and is eaten by the following link.
The first ones are the autotroph organism or producer, such as a vegetable, that can synthesize organic matter from inorganic matter.
The following links are the consumers: herbivores are primary consumers and feed on producers. <u>Carnivores are secondary consumers and feed on herbivores</u>, and so on. The last links are the decomposers, microorganisms that act on dead animals degrading organic matter.
According to the definition of secondary consumers, among the animals on the list, we can assume that the lynx and the wolf are the only secondary consumers. They are both carnivores and feed on herbivores.
On the other hand, the moose and the elk, are both first consumers.
gene for temperature regulation, gene for production of nails, gene for production of fur. these should be the answer because the chart shows them as having the same size and color alleles, which should make them homozygous and dominant.
Answer:
The correct statements are listed below.
Explanation:
Vitamins are organic and minerals are inorganic.
Organic compounds comes from living things.Vitamins generally exist as organic compounds for example all the vitamin such as vitamin A, Thiamine,riboflavin,biotin,pyridoxin,vitamin c,vitamin E, vitamin K exist as organic compounds.
On the other hand minerals are found in inorganic form for example nitrogen is found as nitrate and nitrite,phosphorus is found as phosphate group,phosphoric acid.
Answer:
8.18 × 10 ⁻²¹.
Explanation:
The potential energy may be defined as the energy stored in the rest objects. This energy is important for the maintenance of the concentration gradient in the cell.
The change in the potential energy can be calculated as follows:
W = v2-v1 × q.
Here, the charge of the proton is considered because k+ ions has been used.
W= 0 - ( - 70. 5 mV) × 1.602 * 10^-19 C.
W= 8.18 × 10 ⁻²¹J.
Thus, the answer is 8.18 × 10 ⁻²¹.
