Question

The sum of three consecutive odd integers is 21. x+(x+2)+(x+4)=21 x+(x+1)+(x+2)=21 x+(x+1)+(x+3)=21 x+(x+3)+(x+5)=21

Answer 1

X+(x+2)+(x+4)=21
x+x+x+2+4=21
3x+6=21
(3x+6)/3=21/3
x+2=7
x=7-2
x=5

Answer 5, 7, 9