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ANTONII [103]
3 years ago
6

A sailboat started his journey at 6:30 am and reached his destination at 11:45 pm.If the distance of the journey was 1276.5, wha

t was the average speed of the sailboat?
PLEASE HELPPP IF IT IS RIGHT YOU GET BRAINLIEST ANSWER I NEED IT FAST!!!!!
Mathematics
1 answer:
attashe74 [19]3 years ago
4 0

Answer:

74 mph

Step-by-step explanation:

step 1

Find the total time

A sailboat started his journey at 6:30 am and reached his destination at 11:45 pm

so

from 6:30 am to 12:00 pm ----> there are 5 hours + 30 minutes=5.5 hours

from 12:00 pm to 11:45 pm ----> there are 11 hours + 45 minutes=11.75 hours

The total time is

5.5+11.75=17.25 hours

step 2

Find the average speed

we know that

The average speed is equal to divide the total distance by the total time

speed=\frac{1,276.5}{17.25}= 74\ mph

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Mean is the average. to find mean, you add all the numbers and divide it by how many numbers there are.

68 + 75 + 85 + 80 + 75 + 82 = 465

There are 6 numbers. That means you have to divide 465 by 6 to get the mean.

Divide:

465 / 6 = 77.5

The answer is D. 77.5

Hope this helped☺☺

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If the price of a business math text rose to $120 and this was 10% more than the original price what was the original selling pr
kolezko [41]

Step-by-step explanation:

120*10% =12

10% percent *120

= (10/100)*120

= (10*120)/100

= 1200/100 = 12

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5 0
2 years ago
Give the equation of the line that is perpendicular to y= (1/2)x -1 and passes through the point (3,4)
nexus9112 [7]

Answer: y = -2x + 10

Step-by-step explanation:

Two lines are said to be perpendicular if the product of their slope = -1, that is , if m_{1} is the slope of the first line and m_{2} is the slope of the second line , if the two lines are perpendicular , then m_{1}m_{2} = -1

The equation of the line given :

y = 1/2x - 1

comparing with the equation of line in slope intercept form

y = mx + c , where m is the slope and c is the y - intercept , it implies that

m_{1} = 1/2

Therefore :

m_{2} = -2

To find the equation of the line with slope -2  and passes through the point ( 3 , 4 ) we will use the formula

y-y_{1} = m (x-x_{1} )

y - 4 = -2 ( x - 3 )

y - 4 = -2x + 6

y = -2x + 6 + 4

y = -2x + 10

7 0
3 years ago
What is the equation in point slope form of the line passing through (0,5) and (-2,11)
IRISSAK [1]

The equation of the line passing through (x_1,y_1) and (x_2,y_2) is

\frac{x-x_1}{y-y_1} =\frac{x_2-x_1}{y_2-y_1}. Here

\frac{y_2-y_1}{x_2-x_1} is the slope of the line.

Substituting numerical values, the equation of the line is

\frac{x-0}{y-5} =\frac{-2-0}{11-5} \\ \frac{x}{y-5} =-\frac{1}{3} \\ 3x=5-y\\ 3x+y=5

The equation of the line is 3x+y=5

6 0
3 years ago
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