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Airida [17]
3 years ago
5

Write an equation of the line below

Mathematics
1 answer:
rodikova [14]3 years ago
5 0
Y = 3/1x + 1

Would you like me to explain how to find these?
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Marina spent $13.50 at the grocery store. She bought pears, kiwis, and pineapples. Pears cost $0.50 each, pineapples cost $1.50
MArishka [77]

Answer:

Number of pineapples= 10

number of pears = 19

number of kiwis = 10 -2 = 8

Step-by-step explanation:

Cost of a pear = $ 0.50

Cost of a pineapple = $ 1.5

cost of a kiwi = $ 0.3

Let the pineapples = p

Number of pears = 9 + p

Number of kiwis = p - 2

The cost is

0.15 p + 0.5 (9 + p) + 0.3 (p - 2) = 13.50

0.15 p + 4.5 + 0.5p + 0.3 p - 0.6 = 13.50

0.95 p = 9.6

p = 10

 

8 0
3 years ago
Read 2 more answers
For the graph below, what should the domain be so that the function is at least 300?
tatiyna
Y = -2x^2 + 50x + 300
-2x^2 + 50x + 300 ≥ 300
-2x^2 + 50x ≥ 0
-2x^2 ≥ -50x
x^2 ≤ 25x
x ≤ 25

Therefore, required domain is 0 ≤ x ≤ 25
4 0
3 years ago
Read 2 more answers
Helppp meeee please
IrinaK [193]

Answer:

True.

Step-by-step explanation:

It would be better if it was clearer, but I stand by my answer. "True".

6 0
3 years ago
Which of the following expressions can be used to complete the equation below Secx / 1+cot^2x=
svlad2 [7]

Answer: D) Tan x sin x

<u>Step-by-step explanation:</u>

\dfrac{sec}{1+cot^2}\\\\\\=\dfrac{1}{cos}\cdot \dfrac{1}{1+cot^2}\\\\\\=\dfrac{1}{cos}\cdot \dfrac{1}{1+(\frac{cos}{sin})^2}\\\\\\=\dfrac{1}{cos}\cdot \dfrac{1}{(\frac{sin^2}{sin^2})+(\frac{cos^2}{sin^2})}\\\\\\=\dfrac{1}{cos}\cdot \dfrac{sin^2}{sin^2+cos^2}\\\\\\=\dfrac{1}{cos}\cdot \dfrac{sin^2}{1}\\\\\\=\dfrac{sin\cdot sin}{cos\cdot 1}\\\\\\=\boxed{tan\cdot sin}

3 0
4 years ago
H=255-21t-16t^2<br><br> PLEASE HELP!!
Colt1911 [192]

Answer:

3.15 seconds is the answer.

<u>Explanation</u>

when the ball touches the ground, h =0

hence,

0=255-21t-16t²

16t²+21t-225=0

here a=16 ,b=21, c= -225

t=   \frac{ - b± \sqrt{ {b }^{2}  - 4ac} }{2a} \\  \\ t=   \frac{ - 21± \sqrt{ {21}^{2}  - 4 \times 16 \times  - 225} }{2 \times 16} \\  =  \frac{ - 21 ± \sqrt{441 - ( - 14400)} }{32} \\  =  \frac{ - 21± \sqrt{14841} }{32}  \\  =  \frac{ - 21±121.82}{32}  \\  \\ t =   \frac{ - 21 + 121.82}{32}  \: or \:  \: t =  \frac{ - 21 - 121.82}{32}  \\ t = 3.15 \:  \: or \:  \: t =  - 4.46

time cannot be negative, hence t = -4.46 can be avoided

The ball takes 3.15 seconds to hit the ground.

4 0
3 years ago
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