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CaHeK987 [17]
3 years ago
7

I am totally confused trying to help my son, on this problem

Mathematics
1 answer:
sladkih [1.3K]3 years ago
5 0

Answer: x=4

Step-by-step explanation: You have to distribute the negative signs

x - (4x-7)= 5x-(x+21)

x - 4x + 7 = 5x - x - 21

- 3x + 7 = 4x - 21

28 = 7x

X = 4

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Mama L [17]
Answer in the document below.

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A factory inspector found flaws in 2 out of 12 wooden boxes. What is the experimental probability that the next wooden box will
MrMuchimi

The experimental probability that the next wooden box will be flawed is \frac{3}{13}

<u>Explanation:</u>

Given:

2 out of 12 wooden boxes is flawed.

Experimental probability that the next wooden box will be flawed = ?

If next wooden box is inspected, the total number of wooden box checked will be 12 + 1 = 13

If the next wooden box is flawed, then the number of flawed boxes would be 2+1 = 3

Thus, the experimental probability that the next wooden box will be flawed is \frac{3}{13}

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3 years ago
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Ostrovityanka [42]

Answer:

1: 1 & 5

2: 4 & 5

3: 6 & 8

4: 2 & 4

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3 years ago
Content-disposition=file
Artemon [7]

The rules are very simple: an angle is acute if it's less than 90°, whereas it is obtuse if it's more than 90°.

So, for the first task, you just need to compare the given angle with 90°. If the angle is less than 90°, it's acute. Otherwise, it's obtuse.

Moving on, angle B is complement of a angle A if A+B=90. So, for example, the complement of the first angle is 80, because 10+80=90. Note that this implies that obtuse angles don't have a complement.

Finally, angle B is supplement of a angle A if A+B=180. So, for example, the complement of the first angle is 170, because 10+170=180.

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3 years ago
PLEASE HELP:
Lady bird [3.3K]

Answer: (A) The image of JKL after a 90° counterclockwise about the origin is shown in figure 1. (B) The image of JKL after a reflection across the y-axis is shown in figure 2.

Explanation:

(A)

From the given figure it is noticed that the coordinate points are J(-4,1), K(-4,-2) and L(-3,-1).

If a shape rotate 90 degree counterclockwise about the origin, then,

(x,y)\rightarrow (-y,x)

J(-4,1)\rightarrow J'(-1,-4)

K(-4,-2)\rightarrow K'(2,-4)

L(-3,-1)\rightarrow L'(1,-3)

Therefore, the vertex of imare are  J'(-1,-4),  K'(2,-4) and  L'(1,-3). The graph is shown in figure (1).

(B)

If a figure reflect across the y-axis then,

(x,y)\rightarrow (-x,y)

J(-4,1)\rightarrow J''(4,1)

K(-4,-2)\rightarrow K''(2,-4)

L(-3,-1)\rightarrow L''(3,-1)

Therefore, the vertex of imare are  J''(4,1),  K''(2,-4) and  L''(3,-1). The graph is shown in figure (2).

8 0
3 years ago
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