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3 years ago

A block measure 22 cm by 11 cm by 7 cm.

Mathematics

1 answer:

bearhunter [10]3 years ago

7 0

Answer: 2,500 blocks

Step-by-step explanation:

Hi, to answer this question we have to calculate both volumes:

Volume of a rectangular prism= length x width x height

Volume of the block = 22 x 11 x 7 = 1,694 cm3

Before calculating the volume of the wall, we have to convert the measures in m to cm:

Since:

1m = 100 cm

5 1/2 m x 100 = 550 cm (length)

3 1/2 m x 100 =350 cm (height)

Volume of the wall = 550 x 22 x 350= 4,235,000 cm3

Finally:

Volume of the wall /Volume of the block = 4,235,000 / 1,694 = 2,500 blocks.

Feel free to ask for more if needed or if you did not understand something.

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The position of an object moving along a straight line for

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Answer:

at 2/3 seconds

Step-by-step explanation:

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The distance between the objects is

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The time the distance between the two object is at minimum is when the distance is 0

That is, when

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4 years ago

Mrs. Smith is making cookies. Her recipe calls for 6/8 cup of white sugar and 2/4 cup of brown sugar. How much sugar will Mrs. S

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3 years ago

5.62 as a whole number in simplest form

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3 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

kompoz [17]

$f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}$

is a proper joint density function if, over its support, $f$ is non-negative and the integral of $f$ is 1. The first condition is easily met as long as $C\ge0$ . To meet the second condition, we require

$\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}$

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$f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz$

$\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}$

Then

$\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy$

$\approx\boxed{0.12886}$

c. This probability can be found by simply integrating the joint density:

$\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz$

$\approx\boxed{0.012262}$

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3 years ago

What is illinois basketball currently ranked in their region?

AlekseyPX

Answer:

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3 years ago