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salantis [7]
3 years ago
5

Use the formula Pt= P0e^rt. where Pt is the amount after t years, P0 is the initial amount, t is the rate of interest, and t is

the time period, to complete the table.

Mathematics
1 answer:
BigorU [14]3 years ago
5 0

Answer:

Step-by-step explanation:

From the given formula,

P(t)=P(0)e^{rt}

\frac{P(t)}{P(0)}=e^{rt}

\text{ln}[\frac{P(t)}{P(0)}]=\text{ln}[e^{rt}]

\text{ln}[\frac{P(t)}{P(0)}]=rt

Now we put the values in the formula to get the values of the blank spaces in the table,

1). \text{ln}[\frac{984}{800}]=5r

   r = \frac{0.207}{5}

   r ≈ 4.2%

2). \text{ln}[\frac{1464}{1200}]=4r

   r = \frac{0.19885}{4}

   r = 0.0497

   r = 5%

3). \text{ln}[\frac{1111.5}{950}]=0.045t

   t = \frac{0.157}{0.045}

   t = 3.5 years

4). \text{ln}[\frac{775}{620}]=3.7t

   t = \frac{0.22314}{0.037}

   t ≈ 6 years

5). \text{ln}[\frac{1066.8}{840}]=8r

   r = \frac{0.239}{8}

   r ≈ 3%

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30%

Step-by-step explanation:

1L = 1000ml

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300 ÷ 10 = 30%

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dusya [7]

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The graph of y = 1/2 x2 + 2x + 3 is shown. What are the solutions to the equation 1/2 x2 + 2x + 3 = x + 7?
kirill [66]

Answer:

Step-by-step explanation:

Let's organise our information :

  • the function is (1/2)x²+2x+3

we want to khow the value of x that gives us : (1/2)x²+2x+3=x+7

Now the trick is to write this expression as a quadratic equation with zero at one side :

  • (1/2)x²+2x+3=x+7
  • (1/2)x²+2x+3-x-7=0
  • (1/2)x²+x-4=0

Now let's solve this equation :

  • a= 1/2
  • b= 1
  • c= -4

Δ=1²-4*(1/2)*(-4)

 = 9

So we have two solutions :

  • \left \{ {{y=\frac{-1-3}{2*0.5} } \atop {x=\frac{-1+3}{2*0.5} }} \right.
  • y= -4
  • x= 2

So the solutions are -4 and 2

3 0
3 years ago
Triangle EFG has coordinates E (-4,4), F (-4,-2), and G (2,-2). Triangle JKL will be a dilation of triangle EFG with a scale fac
denis-greek [22]

The point L is plotted at A. (1, -1).

Step-by-step explanation:

Step 1:

First, we plot the coordinates of both triangles.

The coordinates of the triangle EFG are as follows;

E = (-4, 4), F = (-4, -2), and G = (2, -2).

The coordinates of triangle JKL are;

J = (-2, 2), K = (-2, -1), and L = (x, y).

Step 2;

Next, we need to find the distances between at least two coordinates for both triangles.

The distances between vertical lines are found by calculating the difference in y values while for horizontal lines, the distances are found by calculating the difference between the x values.

The distance of EF = 4-(-2) =6.

The distance of JK = 2-(-1)= 3.

The distance of FG =2-(-4)= 6.

The distance of KL =  (Scale factor)(the distance of FG),

The distance of KL= (\frac{1}{2} )(6) = 3.

Step 3;

So the point L is 3 points away from point k on the x axis.

(x, y) = (-2+3, 1) = (1, -1).

So point L is plotted at option A. (1, -1).

8 0
3 years ago
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