For this problem, 0.25 in = 50 m. So
11 in = (11 in) • (50/0.25 m/in) = 2200 m
Alternatively, if 0.25 in = 50 m, that means 1 in = 200 m. So 11 in = 11 (200 m) = 2200 m.
0.17
yuh this is correct lol
<h3>
Answer is the ratio 1000:193:61</h3>
Explanation
1 liter = 1000 mL
For every 1000 mL of water, we need 193 mL of sucrose and 61 mL of saline solution.
The ratio is therefore 1000:193:61
We cannot simplify this ratio any further because the GCF of those three terms is 1.
A quick way to see this is to look at how 1000 = (2*5)^3 has prime factors 2 and 5, but 2 nor 5 are factors of 193 and 61. So only 1 is a factor of all three values 1000, 193, 61
Answer:
here is no question sorry
