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shusha [124]
3 years ago
15

John and alicia are asked to clean the barn. john can clean the barn by himself in 3 hours and together they can clean the barn

in 1 7/8 hours. how long would it take alicia to clean the barn by herself?
Mathematics
2 answers:
Pie3 years ago
8 0

Answer:

Alicia will take 5 hours to clean the barn.

Step-by-step explanation:

John and Alicia are asked to clean the barn.

John can clean the barn alone in 3 hours.

So work done in one hour = \frac{1}{3}

Let Alicia takes x hours to clean the barn alone so work done in one hour by Alicia = \frac{1}{x}

Now it is given in the question that together they can clean the barn in 1\frac{7}{8} hour or \frac{15}{8} hours.

So work done together in one hour = \frac{1}{\frac{15}{8} }=\frac{8}{15}

Now we know work done in one hour by John + work done in one hour by Alicia = work done in one hour by both.

\frac{1}{x}+\frac{1}{3}=\frac{8}{15}

\frac{3+x}{3x}=\frac{8}{15}

15(3+x) = 8 (3x) [By cross multiplication]

45 + 15x = 24x - 15x

45 = 9x

x = \frac{45}{9} = 5

Therefore, Alicia will take 5 hours to clean the barn by herself.

Flura [38]3 years ago
7 0
1 and 1/8 of an hour because Alisha took away that amount of time from johns time.<span />
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Jessie says to round 736,400 to the nearest ten thousand ,he will round to 770,000. is he right? explain.
djverab [1.8K]

no because if your rounding 736,400 it will be 740,000 if its 4 or less you let it rest if its 5 or more it rises


3 0
3 years ago
A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and
pav-90 [236]

Answer:

ans=13.59%

Step-by-step explanation:

The 68-95-99.7 rule states that, when X is an observation from a random bell-shaped (normally distributed) value with mean \mu and standard deviation \sigma, we have these following probabilities

Pr(\mu - \sigma \leq X \leq \mu + \sigma) = 0.6827

Pr(\mu - 2\sigma \leq X \leq \mu + 2\sigma) = 0.9545

Pr(\mu - 3\sigma \leq X \leq \mu + 3\sigma) = 0.9973

In our problem, we have that:

The distribution of the number of months in service for the fleet of cars is bell-shaped and has a mean of 53 months and a standard deviation of 11 months

So \mu = 53, \sigma = 11

So:

Pr(53-11 \leq X \leq 53+11) = 0.6827

Pr(53 - 22 \leq X \leq 53 + 22) = 0.9545

Pr(53 - 33 \leq X \leq 53 + 33) = 0.9973

-----------

Pr(42 \leq X \leq 64) = 0.6827

Pr(31 \leq X \leq 75) = 0.9545

Pr(20 \leq X \leq 86) = 0.9973

-----

What is the approximate percentage of cars that remain in service between 64 and 75 months?

Between 64 and 75 minutes is between one and two standard deviations above the mean.

We have Pr(31 \leq X \leq 75) = 0.9545 = 0.9545 subtracted by Pr(42 \leq X \leq 64) = 0.6827 is the percentage of cars that remain in service between one and two standard deviation, both above and below the mean.

To find just the percentage above the mean, we divide this value by 2

So:

P = {0.9545 - 0.6827}{2} = 0.1359

The approximate percentage of cars that remain in service between 64 and 75 months is 13.59%.

4 0
3 years ago
4. Solve the following inequality: 3y-1 less than 3
mylen [45]

3y - 1 < 3


Isolate the y. Treat the less than or equal like an equal sign.

Do the opposite of PEMDAS. First, add 1 to both sides

3y - 1 (+1) < 3 (+1)

3y < 4

Next, divide 3 from both sides

3y/3 < 4/3

y < 4/3

y < 4/3 is your answer

hope this helps

3 0
3 years ago
The lines intersect at point C. What is the value of x?
Agata [3.3K]

<u>Answer:</u>

The correct answer option is 21.

<u>Step-by-step explanation:</u>

We know that the given lines PW and AD intersect at the point C.

Therefore, the two given angles are equal to each other and we can write them in the form of an equation as:

(4x - 4)° = (3x + 17)°

Solving for x to get:

4x - 4 = 3x + 17

4x - 3x = 4 + 17

x = 21

Therefore, the value of x is equal to 21.

5 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!! Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance t
Sveta_85 [38]

Answer:

The answer to your question is Advance = $35 and same-day = $40

Step-by-step explanation:

Advanced = a

Same-day = s

Equations

                       a +     s  = 75               ----- (I)

                  20a + 35s = 2100            ----- (II)

Process

1.- Solve the equations by elimination.

Multiply equation I by -20

                     -20a - 20s = -1500

                      20a + 35s = 2100

Simplify

                        0   + 15s = 600

Solve for s                  s = 600/15

                                    s = $ 40        

Substitute "s" in equation I to find "a"

                       a   +   40  = 75

Solve for a

                       a    = 75  - 40

                       a = 35

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3 years ago
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