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3 years ago

Verify this trig function. tanysiny = secy-cosy ?

1 answer:

6 0

$LHS\\ \\ =\tan { y } \sin { y } \\ \\ =\frac { \sin { y } }{ \cos { y } } \cdot \sin { y }$

$\\ \\ =\frac { \sin ^{ 2 }{ y } }{ \cos { y } } \\ \\ =\frac { 1-\cos ^{ 2 }{ y } }{ \cos { y } }$

$\\ \\ =\frac { 1 }{ \cos { y } } -\frac { \cos ^{ 2 }{ y } }{ \cos { y } } \\ \\ =\sec { y } -\cos { y } \\ \\ =RHS$

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Abc congruent to pqr which of the following congruence statement is correct

rusak2 [61]

Answer:

I know the answer

Step-by-step explanation:

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3 years ago

Joanne earns $720 a week. She spends 1/3 of her money on rent and 3/4 of the remaining money on groceries. How much money does s

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3 years ago

Read 2 more answers

3. A set of n = 18 pairs of scores (X and Y values) has SSX = 20, SSY = 80, and SP = 10. If the mean for the X values is MX = 8

Karo-lina-s [1.5K]

Answer:

a. Pearson Correlation

r= $\frac{1}{4}$ or 0,25

b. The regression equation is

$Y = 6+ 0,5 *X$

Step-by-step explanation:

a. Pearson Correlation

Using the equation for Pearson correlation:

$r = \frac{SP}{\sqrt{(SS_{x} * SS_{y})} }$

$r= \frac{10}{\sqrt{(20 * 80)} }$

$r=\frac{10}{\sqrt{1600} }$

$r=\frac{10}{40} =\frac{1}{4} = 0,25$

b. Regression

Using regression equation

1. $Y = a+ b *X$

2. $a= m_{y} - b* m_{x}$

3. $b= \frac{SP}{SS_{x} }$

So replacing first 'b' because is content in 'a' equation

$b= \frac{SP}{SS_{x} }$

$b= \frac{10}{20}$

$b= \frac{1}{2} = 0,5$

Knowing 'b' can know 'a' and complete the equation

$a= m_{y} - b* m_{x}$

$a= 10 - 0,5* 8$

$a= 6$

Replacing in the equation 1:

1. $Y = a+ b *X$

$Y = 6+ 0,5 *X$

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3 years ago

An airplane manufacturer needs to purchase an aluminum alloy for use in constructing a part for their new line of jumbo jets. It

Nostrana [21]

Answer:

Step-by-step explanation:

Hello!

In this example, you have 3 populations determined by each aluminum alloy A, B, and C and want to test if their tensile strength is the same or not. So the study variable is the tensile strength of the aluminum and it is tested in each sample taken of each alloy. The parameters of interest are the average tensile strength of each alloy.

The best statistical procedure to compare these three population is an ANOVA test of one factor(tensile strength) with three levels (alloy A, alloy B, and alloy C)

I hope it helps!

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3 years ago

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aleksandrvk [35]

This is a working backwards problem. You know he has $35 at the end. Before he gave his brother $5, he would have $40, which is half of what he had before he bought the clothes, so he would have had $80. Before he spent the $40 on shoes, he would have had $120, so the answer is $120.

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3 years ago