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natta225 [31]
4 years ago
12

Match the term to its description.

Biology
1 answer:
Lyrx [107]4 years ago
8 0
Core D

Chromosphere C

Convective zone A

Radiative zon B
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Which phase of a clinical trial is the first phase to study a pharmaceutical product used by people who have the medical conditi
Phoenix [80]
I think it would be phase 1 (sorry if I’m wrong)
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The passage of IgG antibodies from mother to fetus illustrates: A. natural immunity. B. cell-mediated immunity. C. passive immun
aalyn [17]

The passage of IgG antibodies from mother to fetus illustrates passive immunity.

  • Antibodies produced outside the body can protect a person from contracting a disease, or they can give passive immunity.
  • Because antibodies are not regenerated as frequently as they would be in a person with a functioning immune system, passive immunity is typically transient.
  • Immunity that is transferred from mother to kid is known as maternal passive immunity or natural passive immunity.
  • Antibodies are transferred to the unborn child by the placenta while they are still in the womb and can offer protection against the corresponding infections in the weeks and months after delivery.
  • An infant's passive immunity to disease is maintained after birth due to antibodies contained in breast milk, particularly in colostrum, the protein-rich milk produced in the first few days after birth.
  • The importance of maternal passive immunity for safeguarding infants until their own immune system is mature enough to protect them.

learn more about passive immunity here: brainly.com/question/21480961

#SPJ4

7 0
2 years ago
Define the terms "nature" and "nurture in the<br> context of the Nature vs. Nurture controversy.
Karo-lina-s [1.5K]
Nature refers to your genetic predisposition to be a certain way and nurture refers to the effects that our parents or people who raised us have on us
4 0
3 years ago
8. What are 2 reasons scientific ideas and explanation changes?
alexandr1967 [171]

Answer:over time as our evidence improves. The more experiments we do, and the more data we collect, the better our scientific ideas become.

Explanation:

5 0
3 years ago
Please provide details for this problem. I got 3.24; therefore accept the null hypothesis.
juin [17]

Answer:

See the answer below

Explanation:

The Chi-square (X^2) is calculated by the formula:

X^2 = \frac{(O - E)^2}{E} where O = observed frequency and E = expected frequency

A standard dihybrid cross is expected to give 9:3:3:1 phenotypic ratio.

Phenotype               O                  E                                  X^2

Round yellow          104       9/16 x 160 = 90          \frac{(104 - 90)^2}{90} = 2.18

Round green            27        3/16 x 160 = 30           \frac{(27 - 30)^2}{30} = 0.30

wringled yellow         27        3/16 x 160 = 30           \frac{(27 - 30)^2}{30} = 0.30

wrinkled green          2          1/16 x 160 = 10              \frac{(2 - 10)^2}{10} = 6.40

Total  X^2 value to two decimal places = 9.18

Degree of freedom = (n-1) = 4 -1 = 3

Critical  X^2 value at 95% probabillity level = 7.815

<em>Since the calculated  </em>X^2<em> si more than the critical  </em>X^2<em> value, </em><em>the null hypothesis is rejected. </em>

7 0
3 years ago
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