All categories

3 years ago

Which equation is correct?

1 answer:

8 0

The correct equation is the last one, where secx =hypotenuse ÷ adjacent, secx is the inverse of cosx, and if you recall, cosx=adjacent÷hypotenuse

You might be interested in

There’s a picture about and you have to balance them.

oksano4ka [1.4K]

Answer and Step-by-step explanation:

For these, you have to make sure the same amount of moles are on each side of the chemical equation.

$1ZN + 2HCL$ → $1ZnCL_{2} + H_{2}$

$1SiO_{2} + 4HF$ → $SiF_{4} + 2H_{2} O$

$12HCIO_{4} + 1P_{4} O_{20}$ → $4H_{3}PO_{4} + 6Cl_{2} O_{7}$

These are the balanced equations.

#teamtrees #WAP (Water And Plant)

3 0

3 years ago

You are enclosing a circular flower garden with a fence that costs $2.99 per foot. The radius of the garden is 7 feet. How much

tangare [24]

Did it too fast I was wrong

5 0

4 years ago

Read 2 more answers

Finding an Equation of a Tangent Line In Exercise, use implicit differentiation to find an equation of the tangent line to the g

Karo-lina-s [1.5K]

Answer:

$y=\frac{4}{3}-\frac{x}{3e}$

Step-by-step explanation:

Equation of tangent line of given function at (e,1) is found by implicitly differentiating the given function w.r.to x

$y^{2}+ln(xy)=2\\\\y^{2}+ln(x)+ln(y)=2\\\\\frac{d}{dx}(y^{2}+ln(x)+ln(y))=\frac{d}{dx}(2)\\\\2y\frac{dy}{dx}+\frac{1}{x}+\frac{1}{y}\frac{dy}{dx}=0\\\\\frac{dy}{dx}(2y+\frac{1}{y})=-\frac{1}{x}\\\\\frac{dy}{dx}=-\frac{y}{x(2y^{2}+1)}\\\\at (e,1)\\\\\frac{dy}{dx}=-\frac{1}{e(2+1)}\\\\\frac{dy}{dx}=\frac{1}{3e}$

Equation of tangent line is

y-y₁=m(x-x₁)

at (e,1)

$y-1=-\frac{1}{3e}(x-e)\\\\y=1-\frac{1}{3e}(x-e)\\\\y=1+\frac{1}{3}-\frac{x}{3e}\\\\y=\frac{4}{3}-\frac{x}{3e}\\$

6 0

4 years ago

A stage designer is making a rectangular drape that is 7 yards in length and 16 yards in width. The fabric for the drape cost $2

USPshnik [31]

Yard to square yard
example: 1yard*1 = 1square yard so 6*6=36 square yards. 7*7=42
36*2.90=104.40
42*2.90=121.8
104.40+121.8=$226.20

6 0

3 years ago

Building A is 255 meters taller than building B. If the height of building A is subtracted from twice the height of building B,

garri49 [273]

Answer:

A = 744 meters B = 489 meters

Step-by-step explanation:

A = B + 255

2B - A = 234

-2B -2B Subract the -2B from both sides

-A = -2B + 234

A = 2B - 234 Divide by -1 to get A alone

B + 255 = 2B - 234 Set both equations equal to each other

- B -B

255 = B - 234

+234 +234

489 = B

Plug 234 in for B in the original equations

A = 489 + 255

A = 744

8 0

3 years ago