The question is down below

Mathematics

1 answer:

dmitriy555 [2]3 years ago

8 0

Answer:

Step-by-step explanation:

We must calculate the lateral area of a cylinder.

The formula is:

$A=2\pi rH$

r - radius

H - height

We have H = 6 cm and r = 3.5.

Substitute:

$A=2\pi(3.5)(6)=42\pi\ cm^2$

Use $\pi\approx\dfrac{22}{7}$

$A\approx42\left(\dfrac{22}{7}\right)=(6)(22)=132\ cm^2$

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The table below shows some values of a linear function. What are the missing values

Black_prince [1.1K]

Answer:

Step-by-step explanation:

to get to 18 from 15, you add three.

You keep adding three to every number for the y values since it it a linear function. The x values went up by 1 and the y values went up by 3.

5 0

3 years ago

find the zeros of 2x^2 - 16x + 27 using the quadratic formula. be sure to simplify the expression. Can someone please show me ho

____ [38]

For a quadratic of the form $f(x)=ax^2+bx+c$ , we have the quadratic formula
$x=\dfrac{-b \pm \sqrt{b^2 -4ac} }{2a}$ ,
where a is the coefficient (number before the variable) of the squared term, b is the coefficient of the linear term, and c is the constant term.

So, given $2x^2-16x+27=0$ , we can get that $a=2, \ b=-16$ , and $c=27$ . We substitute these numbers into the quadratic formula above.

$x=\dfrac{-(-16) \pm \sqrt{(-16)^2 -4(2)(27)} }{2(2)}$

$x=\dfrac{16 \pm \sqrt{(256 -216)} }{4}$

$x=\dfrac{16 \pm \sqrt{40} }{4}$

$x=\dfrac{16 \pm 2\sqrt{10} }{4}$

$x=4+ \frac{\sqrt{10}}{2}, \ x=4- \frac{\sqrt{10}}{2}$

This is our final answer.

If you've never seen the quadratic formula, you can derive it by completing the square for the general form of a quadratic. Note that the $\pm$ symbol (read: plus or minus) represents the two possible distinct solutions, except for zero under the radical, which gives only one solution.