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lisabon 2012 [21]
3 years ago
7

Monica is mixing some custom-colored paint for her house. The color she wants requires 3⁄4 ounce of blue dye and 2⁄3 of an ounce

of pink dye mixed with each gallon of white paint base. How much dye is needed to mix 8 gallons of paint?
Mathematics
2 answers:
Mariulka [41]3 years ago
5 0

Answer:

11 1/3 ounces

Step-by-step explanation:

Genrish500 [490]3 years ago
4 0

Ounce of blue dye mixed with one gallon of white paint base = 3/4

Ounce of blue dye mixed with eight gallons of white paint base = \frac{3}{4} (8)

= 3 × 2

=6

Ounce of pink dye mixed with one gallon of white paint base = 2/3

Ounce of pink dye mixed with eight gallons of white paint base = \frac{2}{3} (8)

= 16/3

= 5.3

Hence, 6 ounce of blue dye and 5.3 ounce of pink dye are needed to mix with 8 gallons of paint.

=6


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solniwko [45]
\bf h=-9.8t^2+45t+1.2\implies 64.5=-9.8t^2+45t+1.2
\\\\\\
0=-9.8t^2+45t-63.3\\\\
-------------------------------

\bf \qquad \qquad \qquad \textit{discriminant of a quadratic}
\\\\\\
0=\stackrel{\stackrel{a}{\downarrow }}{-9.8}t^2\stackrel{\stackrel{b}{\downarrow }}{+45}t\stackrel{\stackrel{c}{\downarrow }}{-63.3}
~~~~~~
\stackrel{discriminant}{b^2-4ac}=
\begin{cases}
0&\textit{one solution}\\
positive&\textit{two solutions}\\
negative&\textit{no solution}
\end{cases}
\\\\\\
(45)^2-4(-9.8)(-63.3)\implies -456.36

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3 years ago
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Answer:

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Step-by-step explanation:

4 0
2 years ago
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Step-by-step explanation:

Can i have brainliest

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