Question

Monica is mixing some custom-colored paint for her house. The color she wants requires 3⁄4 ounce of blue dye and 2⁄3 of an ounce of pink dye mixed with each gallon of white paint base. How much dye is needed to mix 8 gallons of paint?

Answer 1

Answer:

11 1/3 ounces

Step-by-step explanation:

Answer 2

Ounce of blue dye mixed with one gallon of white paint base = 3/4

Ounce of blue dye mixed with eight gallons of white paint base = $\frac{3}{4} (8)$

= 3 × 2

=6

Ounce of pink dye mixed with one gallon of white paint base = 2/3

Ounce of pink dye mixed with eight gallons of white paint base = $\frac{2}{3} (8)$

= 16/3

= 5.3

Hence, 6 ounce of blue dye and 5.3 ounce of pink dye are needed to mix with 8 gallons of paint.

=6