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lisabon 2012 [21]
3 years ago
7

Monica is mixing some custom-colored paint for her house. The color she wants requires 3⁄4 ounce of blue dye and 2⁄3 of an ounce

of pink dye mixed with each gallon of white paint base. How much dye is needed to mix 8 gallons of paint?
Mathematics
2 answers:
Mariulka [41]3 years ago
5 0

Answer:

11 1/3 ounces

Step-by-step explanation:

Genrish500 [490]3 years ago
4 0

Ounce of blue dye mixed with one gallon of white paint base = 3/4

Ounce of blue dye mixed with eight gallons of white paint base = \frac{3}{4} (8)

= 3 × 2

=6

Ounce of pink dye mixed with one gallon of white paint base = 2/3

Ounce of pink dye mixed with eight gallons of white paint base = \frac{2}{3} (8)

= 16/3

= 5.3

Hence, 6 ounce of blue dye and 5.3 ounce of pink dye are needed to mix with 8 gallons of paint.

=6


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