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Len [333]
4 years ago
6

Kaylee needed to fold 586 paper notices for a fundraiser. The notices would be mailed in 22 days. Which expression gives the bes

t estimate of the number of notices she must fold each day to meet her goal? A. 500 ÷ 20 B. 500 ÷ 30 C. 600 ÷ 20 D. 600 ÷ 3
Mathematics
1 answer:
dusya [7]4 years ago
4 0

Answer:

I think the answer would be C. because 586 rounds to 600 and 22 round to 20.

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What is the halfway between 5.3 and 5.4
murzikaleks [220]

Answer:

5.35

Step-by-step explanation:

5.3+5.4/2

10.7/2

5.35

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3 years ago
What value(s) of x will make each equation below true?
kvasek [131]

Answer:

a X=0

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3 years ago
Read 2 more answers
I don't understand this nonsense !
mel-nik [20]
Well first you do 6÷3=2. Then you do 2*5= 10. Also do 20+10=30-15=15. So your answer is 15
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3 years ago
POSSIBLE POINTS
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3 years ago
For number 6, evaluate the definite integral.
maks197457 [2]
\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\
-------------------------------\\\\

\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby 
\begin{array}{llll}
\textit{now let's change the bounds}\\
\textit{by using } u(x)
\end{array}\\\\
-------------------------------\\\\
u(0)=8+2(0)\implies u(0)=8
\\\\\\
u(28)=8+2(28)\implies u(28)=64

\bf \\\\
-------------------------------\\\\
\displaystyle  \cfrac{1}{2}\int\limits_{8}^{64}\ u^{-\frac{2}{3}}\cdot du\implies \cfrac{1}{2}\cdot \cfrac{u^{\frac{1}{3}}}{\frac{1}{3}}\implies \left. \cfrac{3\sqrt[3]{u}}{2} \right]_8^{64}
\\\\\\
\left[ \cfrac{3\sqrt[3]{(2^2)^3}}{2} \right]-\left[ \cfrac{3\sqrt[3]{2^3}}{2}  \right]\implies \cfrac{12}{2}-\cfrac{6}{2}\implies 6-3\implies 3
3 0
3 years ago
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