Answer:
a. 2^6, or 64 opcodes.
b. 2^5, or 32 registers.
c. 2^16, or 0 to 65536.
d. -32768 to 32768.
Explanation:
a. Following that the opcode is 6 bits, it is generally known that the maximum number of opcodes should be 2^6, or 64 opcodes.
b. Now, since the size of the register field is 5 bits, we know that 2^5 registers can be accessed, or 32 registers.
c. Unsigned immediate operand applies to the plus/minus sign of the number. Since unsigned numbers are always positive, the range is from 0 to 2^16, or 0 to 65536.
d. Considering that the signed operands can be negative, they need a 16'th bit for the sign and 15 bits for the number. This means there are 2 * (2^15) numbers, or 2^16. However, the numbers range from -32768 to 32768.
Answer:
1 C
2 D
3 B
4 A
5 D
6 B (the question should state software that manages ...)
7 D
8 C
9 A
10 B
11 C
12 D
13 B
Explanation:
Answer:
create a spreadsheet that totals the cost and calculates 120 percent of the total cost
Pretty sure it’s c! I’m not 100% tho sorry if I’m wrong have a nice day:)
Answer:
return values.remove() + values.remove();
Explanation:
The appropriate expression to complete the method, which is designed to return the sum of the two smallest values in the parameter array number is indicated below in bold font :
public static int
sumTwoLowestElements(int[] numbers)
{
PriorityQueue values = new PriorityQueue<>();
for (int num: numbers)
{ values.add(num);
}
return values.remove() + values.remove();
}
The return statementin programming is often used when a function is ready to return a value to its caller.
