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GaryK [48]
3 years ago
10

A catapult’s lever holds a cannonball. The lever is attached to a tightly held rope. When the rope is released, the lever spring

s forward and launches the cannonball. When the rope is held tightly, which form of energy does it possess?
Mathematics
1 answer:
bazaltina [42]3 years ago
4 0

Answer:The rope has a bunch of Potential Energy.

Step-by-step explanation:

The rope is not moving, but staying still. As an object that can move stays still, it has Potential Energy. If it is moving, then the Potential Energy would decrease at a speed equal to that of the object, and be replaced by Kinetic Energy. I hope this helps.

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WILL GIVE BRAINLIEST
olganol [36]

Answer:

Yes, SAS theorem. Angle ACB and Angle ECD are congruent because of the vertical angles theorem.

Step-by-step explanation:

4 0
3 years ago
Denise and Donna want to exchange secrets from across a crowded whispering gallery. Recall that a whispering gallery is a room w
Yuri [45]

Answer:

34 feet

Step-by-step explanation:

From the question, we are told that:

If the room is 30 feet high at the center and 90 feet wide at the floor,

Entire width of the room = 90 feet = 2a

a = 90/2 = 45

Height of the room = b = 30 feet

Foci (c)² = a² - b²

c = √a² - b²

c = √45² - 30²

c = √1125

c = 33.541019662 feet

Approximately to the nearest whole number = 34 feet

Denise and Donna should each stand 34 ft from the outer wall so that they will be positioned at the foci of the ellipse

7 0
3 years ago
Find the number b such that the line y = b divides the region bounded by the curves y = 36x2 and y = 25 into two regions with eq
Gemiola [76]

Answer:

b = 15.75

Step-by-step explanation:

Lets find the interception points of the curves

36 x² = 25

x² = 25/36 = 0.69444

|x| = √(25/36) = 5/6

thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).

The area of the bounded region is given by the integral

\int\limits^{5/6}_{-5/6} {(25-36 \, x^2)} \, dx = (25x - 12 \, x^3)\, |_{x=-5/6}^{x=5/6} = 25*5/6 - 12*(5/6)^3 - (25*(-5/6) - 12*(-5/6)^3) = 250/9

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

125/18 = \int\limits^{\sqrt{b}/6}_0 {(b - 36 \, x^2)} \, dx = (bx - 12 \, x^3)\, |_{x = 0}^{x=\sqrt{b}/6} = b^{1.5}/6 - b^{1.5}/18 = b^{1.5}/9

125/18 = b^{1.5}/9

b = (62.5²)^{1/3} = 15.75

8 0
4 years ago
Cheryl's making trail mix for a friend she always uses three cups of almonds for every four cups of cashews if Cheryl wants to m
Mkey [24]

Answer:

c

Step-by-step explanation:

3x3=9

4x3=12

4 0
3 years ago
Read 2 more answers
An English teacher wants to know the
AfilCa [17]
320

You add all the numbers together then divide by how many numbers there was. In this case all the numbers added to 6405. You divide by 20 because there were 20 numbers. This will get you to 320.25. The closest answer choice would be 320
7 0
3 years ago
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