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vovangra [49]
3 years ago
11

Luke has $120 to buy two watches that cost $58 each and one chain for $13 . Select the answer that uses reasonable estimation to

decide whether Luke has enough money. 1. Yes, Luke has enough money. $58+$58+$13 is about $50+$50+$10 = $110 .2. Yes, Luke has enough money. $58+$58+$13 $58+$58+$13 is about $55+$55+$10 = $120 . 3.No, Luke does not have enough money. $58+$58+$13= $129 . or 4. No, Luke does not have enough money. $58+$58+$13 is about $60+$60+$10 = $130 $60+$60+$10 = $130 .
Mathematics
2 answers:
Alexus [3.1K]3 years ago
8 0
3. No, Lucas does not have enough money. $58 + 58+ 13 = 129
Lucas would be nine dollars over budget. 

Hope this helped :)
slamgirl [31]3 years ago
3 0

4 is correct

No, Luke does not have enough money. $58+$58+$13 is about $60+$60+$10 = $130


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Graph 5x + 3y = 15 on a graph ​
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Answer:

x and y

Step-by-step explanation:

you have to put 5 on the x axes and 3 on the y axes to cordanate 15

4 0
3 years ago
Mrs.Kennedy is buying pencils for each of 315 students at Hamilton Elementary. The pencils are sold in boxes of tens. How can sh
g100num [7]

Mrs Kennedy is buying pencils for 315 students.

The pencils are sold in boxes of 10.

Therefore the number of pencils she needs to buy should be a multiple of 10, so that she can buy boxes of 10 pencils each.

number of students are 315 but 315 is not a multiple of 10

so we have to round off 315 to the nearest ten, that's 320.

so then she has to buy 320 pencils

number of boxes she needs - 320 / 10 = 32 boxes of pencils

she only needs pencils for 315 students so she will have 5 extra pencils

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4 0
3 years ago
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3 years ago
he two-way table shows the medal count for the top-performing countries in the 2012 Summer Olympics. A 5-column table has 5 rows
Cloud [144]

Answer:

The all-time medal table for all Olympic Games from 1896 to 2018, including Summer Olympic Games, Winter Olympic Games, and a combined total of both, is tabulated below. These Olympic medal counts do not include the 1906 Intercalated Games which are no longer recognized by the International Olympic Committee (IOC) as official Games. The IOC itself does not publish all-time tables, and publishes unofficial tables only per single Games. This table was thus compiled by adding up single entries from the IOC database.[1]

The results are attributed to the IOC country code as currently displayed by the IOC database. Usually, a single code corresponds to a single National Olympic Committee (NOC). When different codes are displayed for different years, medal counts are combined in the case of a simple change of IOC code (such as from HOL to NED for the Netherlands) or simple change of country name (such as from Ceylon to Sri Lanka). As the medals are attributed to each NOC, not all totals include medals won by athletes from that country for another NOC, such as before independence of that country. Names in italic are national entities that no longer exist. The totals of NOCs are not combined with those of their predecessors and successors.

Step-by-step explanation:

7 0
3 years ago
Rewrite with only sin x and cos x.
Annette [7]

Option A

\cos 3 x=\cos x-4 \cos x \sin ^{2} x

<em><u>Solution:</u></em>

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

cos 3x = cos(x + 2x)

We know that,

\cos (a+b)=\cos a \cos b-\sin a \sin b

Therefore,

\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x  ---- eqn 1

We know that,

\sin 2 x=2 \sin x \cos x

\cos 2 x=\cos ^{2} x-\sin ^{2} x

Substituting these values in eqn 1

\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)  -------- eqn 2

We know that,

\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x

Applying this in above eqn 2, we get

\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)

\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}

\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x

Therefore,

\cos 3 x=\cos x-4 \cos x \sin ^{2} x

Option A is correct

7 0
3 years ago
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