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lesya692 [45]
4 years ago
5

What is a Photojournalist

Computers and Technology
1 answer:
Citrus2011 [14]4 years ago
6 0
<span>a journalist who communicates news by photographs.
</span><span>Photojournalism is a particular form of journalism that employs images in order to tell a news story. It is now usually understood to refer only to still images, but in some cases the term also refers to video used in broadcast journalism.</span>
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You are given a string of n characters s[1 : : : n], which you believe to be a corrupted text document in which all punctuation
alexdok [17]

Answer: provided in the explanation section

Explanation:

Given that:

Assume D(k) =║ true it is [1 : : : k] is valid sequence  words or false otherwise

  • To determine D(n)

now the sub problem s[1 : : : k] is a valid sequence of words IFF s[1 : : : 1] is a valid sequence of words and s[ 1 + 1 : : : k] is valid word.

So, from here we have that D(k) is given by the following recorance relation:

D(k) = ║ false maximum (d[l]∧DICT(s[1 + 1 : : : k]) otherwise

Algorithm:

Valid sentence (s,k)

D [1 : : : k]             ∦ array of boolean variable.

for a ← 1 to m

do ;

d(0) ← false

for b ← 0 to a - j

for b ← 0 to a - j

do;

if D[b] ∧ DICT s([b + 1 : : : a])

d (a) ← True

(b). Algorithm Output

      if D[k] = = True

stack = temp stack           ∦stack is used to print the strings in order

c = k

while C > 0

stack push (s [w(c)] : : : C] // w(p) is the position in s[1 : : : k] of the valid world at // position c

P = W (p) - 1

output stack

= 0 =

cheers i hope this helps !!!

8 0
3 years ago
Yall rachits and yall eat butt xD
Trava [24]
Please use this for questions.
6 0
3 years ago
Read 2 more answers
Banking Account
satela [25.4K]

Answer:

Here is the Python script solution.

Explanation:

#!/usr/bin/python

"""Types of bank accounts"""

# Assignment:

# Bank Account Manager - Create a class called Account which will be an abstract

# class for three other classes called CheckingAccount, SavingsAccount and

# BusinessAccount. Manage credits and debits from these accounts through an ATM

# style program.

from __future__ import print_function

def pct_to_dec(num):

"""Returns decimal version of percent"""

dec = float(num) / 100

return dec

class Account(object):

"""Creates an Account"""

def __init__(self, balance, int_rate, act_type, min_balance, **kwargs):

self.balance = balance

self.int_rate = int_rate

self.act_type = act_type

self.min_balance = min_balance

super(Account, self).__init__(**kwargs)

def __str__(self):

"""Returns formatted account type and balance"""

# Charge $25 fee if balance drops below minimum

if self.balance < self.min_balance:

self.balance -= 25

# Add interest

self.balance += round(self.balance * pct_to_dec(self.int_rate), 2)

return '{0}: ${1}'.format(self.act_type, self.balance)

class CheckingAccount(Account):

"""Creates a CheckingAccount Account"""

def __init__(self, **kwargs):

super(CheckingAccount, self).__init__(**kwargs)

class SavingsAccount(Account):

"""Creates a SavingsAccount Account"""

def __init__(self, **kwargs):

super(SavingsAccount, self).__init__(**kwargs)

class BusinessAccount(Account):

"""Creates a BusinessAccount Account"""

def __init__(self, **kwargs):

super(BusinessAccount, self).__init__(**kwargs)

# pylint: disable=C0103

ca1 = CheckingAccount(balance=500, int_rate=0.25, act_type='Checking Account',

min_balance=0)

sa1 = SavingsAccount(balance=50, int_rate=0.50, act_type='Savings Account',

min_balance=0)

ba1 = BusinessAccount(balance=4000, int_rate=0.75, act_type='Business Account',

min_balance=5000)

# Month #1 statement, initial deposits plus interest

print(ca1)

print(sa1)

print(ba1)

print('-------------')

# Month #2 statement plus interest

# Make deposit into checking

setattr(ca1, 'balance', (ca1.balance + 1000))

# Withdraw from checking

setattr(ca1, 'balance', (ca1.balance - 500))

# Make a deposit into savings

setattr(sa1, 'balance', (sa1.balance + 100))

print(ca1)

print(sa1)

print(ba1)

print('-------------')

# Month #3 statement plus interest

# Make deposit into checking

setattr(ca1, 'balance', (ca1.balance + 2500))

# Withdraw from checking

setattr(ca1, 'balance', (ca1.balance - 700))

# Make a deposit into savings

setattr(sa1, 'balance', (sa1.balance + 100))

# Make a deposit into business

setattr(ba1, 'balance', (ba1.balance + 1000))

print(ca1)

print(sa1)

print(ba1)

4 0
4 years ago
True/False: Each individual element of an array can be accessed by the array name and an element number, called a subscript. Tru
Dahasolnce [82]

Answer:

True

Explanation:

3 0
3 years ago
Given a collection of n nuts and a collection of n bolts, arranged in an increasing order of size, give an O(n) time algorithm t
kari74 [83]

Answer:

See explaination

Explanation:

Keep two iterators, i (for nuts array) and j (for bolts array).

while(i < n and j < n) {

if nuts[i] == bolts[j] {

We have a case where sizes match, output/return

}

else if nuts[i] < bolts[j] {

this means that size of nut is smaller than that of bolt and we should go to the next bigger nut, i.e., i+=1

}

else {

this means that size of bolt is smaller than that of nut and we should go to the next bigger bolt, i.e., j+=1

}

}

Since we go to each index in both the array only once, the algorithm take O(n) time.

8 0
4 years ago
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