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lesya692 [45]
3 years ago
5

What is a Photojournalist

Computers and Technology
1 answer:
Citrus2011 [14]3 years ago
6 0
<span>a journalist who communicates news by photographs.
</span><span>Photojournalism is a particular form of journalism that employs images in order to tell a news story. It is now usually understood to refer only to still images, but in some cases the term also refers to video used in broadcast journalism.</span>
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b

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This function receives first_name and last_name, then prints a formatted string of "Name: last_name, first_name" if both names a
pishuonlain [190]

Answer:

Following are the program in the C++ Programming Language.

//set header file

#include <iostream>

//set namespace

using namespace std;

//define class

class format

{

//set access modifier

public:

//set string type variable

 string res;

//define function

 void names(string first_name, string last_name)

 {  

//set if-else if condition to check following conditions

   if(first_name.length()>0 && last_name.length()>0)

   {

     res="Name: "+last_name+", "+first_name;

   }

   else if(first_name.length()>0 and last_name.length()==0)

   {

     res="Name: "+first_name;

   }

   else if(first_name.length()==0 and last_name.length()==0)

   {

     res="";

   }

 }

//define function to print result

 void out(){

   cout<<res<<endl;

 }

};

//define main method

int main() {

//set objects of the class

 format ob,ob1,ob2;

//call functions through 1st object

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 ob.out();

//call functions through 2nd object

 ob1.names("Jhon","");

 ob1.out();

//call functions through 3rd object

 ob2.names("", "");

 ob2.out();

}

<u>Output</u>:

Name: Morris, John

Name: Jhon

Explanation:

<u>Following are the description of the program</u>:

  • Define class "format" and inside the class we define two void data type function.
  1. Define void data type function "names()" and pass two string data type arguments in its parameter "first_name" and "last_name" then, set the if-else conditional statement to check that if the variable 'first_name' is greater than 0 and 'last_name' is also greater than 0 then, the string "Name" and the following variables added to the variable "res". Then, set else if to check that if the variable 'first_name' is greater than 0 and 'last_name' is equal to 0 then, the string "Name" and the following variable "first_name" added to the variable "res".
  2. Define void data type function "out()" to print the results of the variable "res".
  • Finally, we define main method to pass values and call that functions.
3 0
3 years ago
2. Student organizations sometimes require transportation for off-campus activities, and school policy requires students to be o
Dafna11 [192]

Answer:

=IF(B2>=23,"Yes","No")

Explanation:

Given

Name = Kay Colbert

The Name column can't be used to determine the eligibility of a student to the transport.

What is needed is the corresponding age column of Kay's age.

Assume that the age column is B2 and the result column is C2 (See Attachment)

Enter the following in C2

=IF(B2>=23,"Yes","No")

This will return "Yes" without the quotes in cell C2 if B2 is greater than 23

Else, it'll return "No" without the quotes.

To drag the formula to other column, follow the instructions below

Select cell C2.

Rest your cursor in the lower-right corner so that it turns into a plus sign (+), like this:

Drag the fill handle downwards

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Answer:

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There are three types of code that make up a basic website page. HTML governs the structural elements, CSS styles those elements, and JavaScript enables dynamic interaction between those elements.

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2 years ago
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